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51cto college specially sorted out "2014 soft exam-Information Processing technician [exam counseling Summary]" in the soft exam preparation season to help schools pass smoothly! MoreSoftware Proficiency TestFor more information about tutoring and questions, see51cto school-soft test category! View summary: 2014 soft exam-Information Processing technician-test tutoring [summary] 650) This. wid

$, containing copper $7$ parts, should be added to copper how much?Answer:Should be added copper $x $ g. $$ (+ x) \cdot \frac{7}{10} = \times \frac{3}{5} + x$$ $$\rightarrow x = \frac{200}{3}.$$ so should be added copper $\d frac{200}{3}$ G.4. Hard aluminum is $4\%$ copper, $1\%$ manganese, $0.5\%$ magnesium and $94.5\%$ aluminum preparation, melting loss rate according to $1.5\%$ calculation. Manufacturing $250$ kg hard aluminum, how many kilograms of the above materials? (Keep one decimal plac

) ^2 + (2x^2-7x + 6) ^2 = (3x^2-4x + 2) What is the solution of ^2$?Answer:Note that $ (x^2 + 3x-4) + (2x^2-7x + 6) = 3x^2-4x + 2$, so consider swapping elements.Make $x ^2 + 3x-4 = m$, $2x^2-7x + 6 = n$, then $ $m ^2 + n^2 = (m + N) ^2 \rightarrow mn = 0.$$ This can be $ $x ^2 + 3x-4 = 0\rightar Row (x+4) (x-1) = 0 \rightarrow x_1 = -4,\ x_2 = 1,$$ or $$2x^2-7x + 6 = 0 \rightarrow (2x-3) (x-2) = 0 \rightarrow x _3 = {3\over2},\ X_4 = 2.$$ fully, the solution of the original equation is: $ $x _1

Tags: Network Engineer knowledge point 3 years zhenti exam650) This. width = 650; "Title =" wkiol1mi5r3bg69eaaujb1e3hwm643.jpg "src =" http://s3.51cto.com/wyfs02/M00/4C/38/wKiom1Q5Uz_xZKbvAAUQlMeR5lk091.jpg "alt =" wkiom1q5uz_xzkbvaauqlmer5lk091.jpg "/This article from "stick to original, with excellent works..." blog, please be sure to keep this source http://296525818.blog.51cto.com/19860/1562762It is recommended that you carefully record the knowledge points before the test (1) network engine

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}$$ $$\rightarrow \begin{cases}m = -5\\ n = \end{cases}\rightarrow MN = -100.$$4. Known $a ^3 + b^3 + c^3 = a^2 + b^2+ c^2 = A+b+c = 1$, then $abc =? $Answer:by $ $a ^3 + b^3 + c^3-3abc = (A + B + C) (a^2 + b^2 + c^2-ab-bc-ca) $$ and $$ (A + B + c) ^2-(a^2 + b^2 + c^2) = 0$$ $$\ RightArrow 1-3ABC = 1-(ab + BC + CA) = 1\rightarrow ABC = 0.$$5. If $2a = 6b = 3c$, and $ab + BC + CA = 99$, then $2a^2 + 12b^2 + 9c^2 =? $ Answer: $$\begin{cases}a = 3b\\ c = 2b \end{cases} \rightarrow 3b^2 + 2b^2 + 6b^

.$$ easy to know $d $ is odd, so $d = 1$.4. Set $ (A, B) = 1$, proof: $$\left (a^2 + b^2, ab\right) = 1.$$ solution: $$ (A, b) = 1\rightarrow (a^2, b) = 1 \rig Htarrow (a^2 + b^2, b) = 1.$$ similarly available $ (a^2 + b^2, a) = 1$. So $ (a^2 + b^2, AB) = 1$.5. Proof: If $a, b\in\mathbf{n^*}$, then sequence: $a $, $2a$, $\cdots$, $ba $ The number of items that can be divisible by $b $ equals $ (A, b) $.Answer:Make $ (A, B) = d$, $a = da_1$, $b = db_1$, $ (a_1, b_1) = 1$. The original number is

that $\dfrac{n}{p}$ is a prime number if $p > n^{\frac{1}{3}}$.Answer:Suppose $\dfrac{n}{p} = p_1 \cdot k$, where $p _1$ is prime and $p 5. Find the $x $, $y $, $z $ for all primes that satisfy the equation $x ^y + 1 = z$.Answer:$x ^y$ differs from $z $ parity, so $x = 2$. $$\rightarrow 2^y + 1 = z$$ If $y $ is odd, then $z $ is composite, so $y = 2$, $z = 5$.6. Proof: $n > 2$, there must be a prime number between $n $ and $n!$.Answer:Easy to know $ (n!, n!-1) = 1$. The primes in $1\sim n$ can

51cto college specially sorted out "2014 soft exam-Information Processing technician [exam counseling Summary]" in the soft exam preparation season to help schools pass smoothly! For more software proficiency test counseling and questions, please pay attention to the 51cto college-soft exam classification! View summary:2014 soft exam-Information Processing technician-test tutoring [summary]650) This. width = 650; "alt =" popular article "src =" htt

that should be recorded takes time to memorize and copy 10 times, but it is not the main one, you spend more time thinking about what I learned and how to use it. find a free exercise set and conduct carpet bombing to improve your question sensitivity. Do not just do simple questions. It is the best to do real questions. There is no basic level limited. It is an excuse to be unable to do that difficult question! Because the reality is that this year's questions are almost the same, and the dif

introduce "flipping classroom" into online educationAdvantage 8, the first o2j (Online to Job) mode, field study, Shanghai employmentAdvantage 9, one-time admission, lifelong learningAdvantage 10, students enjoy super VIP treatment, open a pair of three "nanny class" serviceFirst stage: Focus on Fundamentals (C # Basics, C # core, c#5.0 new features, Web development Basics, Database Basics)Phase II: Focus on Ascension (task-driven approach, North Wind first taste)Phase III: Project Training (co

1) if the file newdir/file2 does not exist but the directory newdir already exists, what is the result of the following command? Mvfile1newdir/file2file1 will be moved to newdir and renamed as file2file1 will be copied to newdir and named file2. An

Autofs is a very heavy Mount mode and is also the most commonly used Mount mode. Let's talk a little bit about it. Preparations: 1. build an nis server. set up an nfs server. nis and nfs can be the same server. You can try different servers. In this

《C LanguageProgramDesign (three editions), published by Tsinghua1. Appendix A common characters and ASCIICodeTableAppendix B keywords in C LanguageAppendix C Operator and associativity (Who calculates who is first and then calculates)Appendix D

Test instructionsIn some subjects, and remedial classes, each subject eventually required to be fixed to a certain level, you can spend a certain amount of money in the remedial class to a certain level, there is a limit when entering the remedial

Introduction of CASL assembly language grammar Learning an assembly language needs to Master 3 key points: CPU programmable register structure, addressing mode and instruction system, pseudo instruction. 1, cometcpu programmable Register cometcpu

Personal counseling Summary I. Description Since the beginning of November, the school has launched an activity for students of grade 10 to find a few student TAs. students of grade 12 will be given tutoring for students in the evening during their self-study course C LanguageProgramDesign. When I heard this, I felt very excited because I was interested in trying it out. Later, I learned that I only use C language. Although my technology is not

order to bring more Internet access services revenue.Comments: As the current education metropolitan area Network uses the most extensive operation mode, its advantages: simple and stable charging method, access to schools to achieve a certain scale returns better. Disadvantage: A knife-cut fee is easy to arouse the objections of the school, there is unfair. In addition, the most concern for the site operators is that the network access services facing the competition of telecom operators, on t

professors of the organizations you take the test often look, you have to arrange time to read these papers. I have already mentioned that I should try my best to finish reading mathematics in my junior year. I think it is best to finish reading mathematics and completing exercises in the auxiliary books before my junior year's summer vacation, then, if you have financial conditions, you can go to some summer public courses and professional courses (depending on your situation ). I didn't even