udemy data structures and algorithms

node's successor (the node right child is the root of the tree in the left subtree of the lowest value of the point) as the new root, at the same time at the beginning of the subsequent node, the execution of the first two delete algorithm, delete algorithm end.5. B + TreeThe B + Tree of an M-order satisfies the following conditions:(1) Each node has a maximum of M children.(2) root nodes and leaf nodes, each of the other nodes has at least ém/2ù children.(3) The root node has at least two chil

I. Large O notationLarge o notation is not an algorithm. It is used to indicate how quickly an algorithm solves a problem. In general, we describe how quickly a thing is done in terms of time, for example, how many minutes I have completed a computational problem. But the algorithm is difficult to use accurate time to describe, so we use the algorithm to solve the problem of a total number of steps to represent the speed of the algorithm.Using the first two search methods for example, simple fin

starts with two pointers, and two pointers point to both ends of the array. (The word "pointer" is used here to indicate the array data item, not the pointer in C + +.) The pointer on the left, Leftptr, moves to the right, while the pointer on the right, rightptr, moves to the left.In fact, leftptr initialization is at the left of the first data item, and Rightptr is on the right-hand side of the last

Linear table Lookup algorithmSequential LookupBinary lookup (linear table must be already sorted)1 /**binary Find2 * @paramobj3 * @paramvalue4 */5 Public Static voidHalfsort (int[] obj,intvalue) {6 intLen=obj.length;//gets the length of the array7 intMin=0;8 intMax=len-2;9 while(minmax) {Ten intMiddle= (Min+max)/2;//gets the subscript for the middle element of an array One if(obj[middle]==value) { ASystem.out.printl

1#include 2#include 3 voidSelectsort (int*a,intn);//pre-declaring the function to be called4 intMainvoid)5 {6 intK;7 intx[Ten]={2,4,6,8,0,1,3,5,7,9};8 for(k=0;kTen; k++)9printf"%d", X[k]);Tenprintf"\ n"); OneSelectsort (x,Ten); A for(k=0;kTen; k++) -printf"%d", X[k]); -printf"\ n"); theSystem"Pause"); - - return 0; - } + - voidSelectsort (int*a,intN//array elements are pointers, number of arrays + { A intI,j,t;//integer variable at intMin//minimum value, inde

; 1){ - if(Peoples[index]) { incount++; - if(Count = = 3){ toPeoples[index] =false; +Count=0; -leftcount--;//minus 1 for the rest of the population. the } * } $ Panax Notoginseng //put the element under the label -index++; the + //If you have counted to the end of the array, start the number A if(Index > Len-1){ theindex = 0; + } - } $ $ for(i

1 classTrietree ():2 def __init__(self):3Self.root = {}4 5 defAddNode (SELF,STR):6 #each node (root node) in the tree that contains the number of words to that node, and the key that appears after the node.7Nowdict =Self.root8 forIinchRange (len (str)):9 ifStr[i] not inchNowdict:#discover new ways to combineTenNowdict[str[i]] = {'Count'70A'prefix': str[:i+1]} OneNowdict = Nowdict[str[i]]#move to the next node. Anowdict['Count'] + = 1 - - defCount

, card): Table.append (Card)ifTable.count (Card) >=2: whileTable.count (Card) >0:person.append (Table.pop ()) whileLen (hen)!=0 andLen (haa)! =0:#print "tab:", List (table)i = Hen.popleft ()#hen the cards first#print "Hen put", IRefreshtable (hen, i)#Hen Action#print "hen:", List (hen) #print "tab:", List (table)j = Haa.popleft ()#Haa after the card#print "Haa put", JRefreshtable (Haa, J)#haa Action#print "Haa:", List (HAA)#print "tab:", List (table)#print "Next Turn"

One, simple demopublic class Recursion {public static void Main (string[] args) {Test (100);}public static void Test (int n) {if (n = = 0) {Return}SYSTEM.OUT.PRINTLN (n);Test2 (n-1);}}Two, triangle numberpublic class Triangle {public static int GetNumber (int n) {int total= 0;while (n > 0) {Total = Total + N;n--;}return total;}public static int getnumberbyrecursion (int n) {if (n = = 1) {return 1;} else {return n + getnumberbyrecursion (n-1);}}}Test:public class Testtriangle {public static void

Quick sort:/** Quick Sort*/public class QuickSort {/*** Divide arrays*/public static int partition (long arr[],int left, int. Right,long point) {int leftptr = left-1;int rightptr = right;while (true) {Loop, will be smaller than the keyword left in the left sidewhile (Leftptr Loop, will be larger than the keyword left on the right sidewhile (Rightptr > Leftptr arr[--rightptr] > point);if (leftptr >= rightptr) {Break} else {Long tmp = arr[leftptr];ARR[LEFTPTR] = arr[rightptr];ARR[RIGHTPTR] = tmp;

Data structures and algorithms (C # implementation) series --- generalized tree (II) Heavenkiller (original) Public override object key {get {return this. Key ;}} Public override uint degree {get {return this. degree ;}} // Public override uint height {get {return this. Height ;}} Public override bool isempty () // property takes the place of isempty

1#include 2#include 3 4 intBinsearch (intXintV[],intn);//function Declaration5 6 intMain ()7 {8 intarr[]={1,2,3,4,5,6,7,8,9,Ten};9 intas a result, num;Tennum=7; OneResults =binsearch (Num,arr,Ten); A - if(Results 0) -printf"I didn't find!\n ."); the Else -printf"find%d\n in arr[%d]", as a result, num); -System"Pause"); - + return 0; - } + A intBinsearch (intXintV[],intN//function Definition at { - intLow,high,mid;//min, max, Middle - -low=0; -high=n-1; - in

Data structures and algorithms (C # implementation) series --- AVLTree (II) // --------------- Override -------------------- Public override void AttachKey (object _ obj) { If (! IsEmpty ()) Throw new Exception ("My: this node must be a empty tree node! "); This. key = _ obj;

) { returnNULL; } TreeNode* node =NewTreeNode;//noice that [new] should is written out.Node->elem = * (aftorder+length-1); Std::coutStd::endl; intRootindex = 0; for(; rootindex //a variation of the loop { if(Inorder[rootindex] = = * (aftorder+length-1)) Break; } node->left =binarytreefromorderings (inorder, Aftorder, Rootindex); Node->right = binarytreefromorderings (inorder + rootindex + 1, Aftorder + rootindex, Length-(Rootindex + 1)); returnnode;}intMainintarg

Data structures and algorithms (C # implementation) series --- tree (III) Heavenkiller (original) // Overwrite Object. Equals () --- reference type realization Public override bool Equals (object _ obj) { If (_ obj = null) Return false; // this cannot be null If (! (This. GetType () = _ obj. GetType ())) Return false; // The type is not equal. Tree tmpObj = (Tre

Public classSelectionsort { Public Static voidsort (integer[] array) {if(Array = =NULL|| Array.Length = = 0) { return; } Integer mininum=NULL; Integer Miniindex=NULL; for(inti = 0; i ) {Miniindex=i; Mininum=Array[i]; for(intj = i + 1; J ) { if(Array[j] mininum) {Miniindex=J; Mininum=Array[j]; } } if(Miniindex! =i) {swap (array, I, miniindex); } } } Private Static voidswap (integer[] array, integer i, Integer j) {Integer temp=Array[i]

1 Sequence decompression: through * to pass the match*a, B = somelist, First, *mid, last = Somelist, a, *b = Somelist2 using bidirectional queues: From collections import dequeQ = deque (maxlen=5) can be fixed lengthQ = deque () can also be any lengthcan be inserted and removed from both ends, append, Appendleft, pop, popleft3 finding the largest or smallest n elements: using heapq (heap queue)HEAPQ. nlargest (N, Alist) heapq. nsmallest (n, alist) is suitable when n is relatively smallYou can al

(e e);//replace element in collection * "9" void Add (e e);//At the previous position of the current index or the current Adds a new element to the collection at the back of the index position. *//whether or not to add new elements before or after the current index position depends on whether you are traversing sequentially or in reverse order * If it is {@link#next}, insert at the previous position of the current position *//if it is {@link#previous} to inser

The maximum value in the output array A and its subscript#include Data structures and algorithms-maximum values in a string output array

Title: Define the Fibonacci sequence as follows:/0 N=0F (n) = 1 n=1\ f (n-1) +f (n-2) n=2Enter N to find the nth item of the sequence in the quickest way.#include Data structures and algorithms-string Fibonacci to find the nth item