Topic Link: UVA 1308-viva confettiEnumerate the two circles, process all arcs, and then determine whether the midpoint of each arc is visible, the circle where the arc is visible, and the circle below the arc is also visible.#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. UVA 1308-viva Confetti (geometry)
Title Address: UVA 147Test instructions: Given 11 denominations of 100 yuan, 50 yuan, 20 yuan, 10 yuan, and 5 yuan and 2 yuan, 1 yuan, 50 points, 20 points, 10 cents and 5 cents, now given a sum of money, to find out the number of categories that can be composed.Ideas: Subsets and Problems: s={x1, x2, ..., xn} is a set of positive integers, and C is a positive integer. Subsets and problems determine if there is a subset of S S1, so that the sum of eac
UVA-112Tree Summing
Time Limit: 3000MS
Memory Limit: Unknown
64bit IO Format: %lld %llu
Submit StatusDescription
Tree Summing
BackgroundLISP was one of the earliest high-level programming languages and, with FORTRAN, is one of the oldest languages currently being used. Lists, which is the fundamental data structures in LISP, can easily is adapted to r
Topic Link: UVA 1434-yaptchaTitle: Given N and K, ask for the given formula S (n) in the topic.How to solve the problem: Wilson's theorem, when X is prime,((x ?1)!+1)%x ==0, so for the subject. Assuming 3*k+7 is a prime number,[ ( 3 k + 6 " ! + 1 (3k+7 ?[ (3k+6)! 3k+7 ]]=1#include #include #include #include using namespace STD;Const intMAXN =1e6;intans[maxn+5], vis[maxn*4+5];voidPrimetable (intN) {memset(Vis,0,sizeof(VIS)); for
Topic Links:[UVA 10801] Lift hopping[dijkstra][Building Map]Test Instructions Analysis:Starting from the 0 floor, there are a total of n elevators for you to reach the destination K floor. Each elevator to go up a layer to consume t[i] time, and elevator can only stop on a specific floor, transfer elevator to spend 60s of time, and, you can not use the stairs upstairs, can only take the elevator .... (hentai! Q: What is the fastest time to reach the f
UVA 10269 Adventure of Super Mario Title: There is a village, B Castle, village number from 1~a, Castle number from A + 1 ~ a + B. Mario lives in village 1th and the princess is held in A + B castle. Mario has a treasure that allows him to run the distance of L in an instant, but there is a limit to this treasure. The starting or ending point of launching this treasure must be a village or a castle, and cannot pass through the castle. Such treasures o
UVA 12186 another Crisis tree dp////for a node u, there is a K child node, then at least C = (k * T-1)/100 + 1 to//letter, that is c/k >= T/100, then the value of C is k * T /100, take the whole into the upper//will all the sub-node d from small to large sort, take the first C is d[u] Value//purple book on a question, before looking at a long time, feel very good, however has not done, today//experience, very good, note, if a node is a leaf node, Dire
-Permutation TransformerTime limit:MS Memory Limit:0KB 64bit IO Format:%lld %llu SubmitStatusPractice UVA 11922Appoint Description:System Crawler (2014-11-30)Description
Permutation Transformer
Write a program to transform the permutation 1, 2, 3,..., n according to m instructions. Each instruction (a, b) means-to-take-out of the subsequence from the a-th to the b
-th element, reverse it, th
//UVA 11357 Matches////Main topic:////give you n a match, the number of non-negative numbers that can be represented by the n matches, cannot contain a leading 0////Problem Solving Ideas:////F[i] Indicates the number of integers that can be represented by an I match, then f[i + c[j]] + + f[i];//C[j] is the number of matches required by the number J, because when J==0 and i==0, we do not allow such//transfer, because the i=0 is not allowed to use the n
Topic Link: UVA 12307-smallest enclosing RectangleThe two pairs of heel-to-point circumference are rectangular, and the minimum values of all feasible rectangles are enumerated.#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced. UVA 12307-smallest enclosing Rectangle (rotating jam)
Topic Link: UVA 1318-monster TrapEach line 2 points, plus the beginning of the end of one is 202 points, the violent judgment between the point can be reached, can reach the building edge. Because the segments have thickness considerations, the segments are extended a bit and then processed so that the segments that originally shared one end point become intersected. The special case is the three-point collinear, which is to determine whether the poin
Topic Link: UVA 12230-crossing RiversThere is a person to go to the company every day to work. Every time it passes through N rivers. The distance between the home and the company is D. By default, the speed of the land is 1, giving information about the N River. Contains the starting coordinates p, width l, and the speed of the boat.The boat will be back and forth on both sides of the river. People reach the riverbank is. The position of the ship is
Uva-1103ancient MessagesIn order to understand early civilizations, archaeologists often study texts written in ancient languages.One such language, used in Egypt + than, years ago, is based on characters called Hieroglyphs.Figure C.1 shows six hieroglyphs and their names. In this problem, you'll write a program to recognizeThese six characters.Figure C.1:six HieroglyphsInputThe input consists of several test cases, each of which describes a image con
UVA 12125 March of the Penguins topic: There are n on the grid (
n =
) leaf blade with Ni-only penguin on the first piece of Lotus leaf (
0=ni=ten
)。 Due to limited capacity, the lotus leaf can only withstand mi (
1=mi=
The penguin jumps away from Mina. A penguin can jump D (
D= ten 5
) Unit distance. All penguins are asked to gather on the same piece of Lotus leaf. Ask which Lotus leaves can be a pla
A soon-to-be friend asked my question. Khan, how I was a freshman to touch programming!It was written in STL, when UVA hung up and did not go to the test. After the discovery of tle, the vector is still the same as the group. The moment did not think how to solve, first of all, then look.1#include 2#include 3#include 4#include 5#include 6 using namespacestd;7 Const intmaxx= -;8 intMain ()9 {Ten //freopen ("In.txt", "R", stdin); One //freopen (
The first is Uva 147:http://uva.onlinejudge.org/index.php?option=com_onlinejudgeitemid=8page=show_problem problem=83After the careful reading of the problem found or complete backpack, just need to deal with floating point. That is, the face value of all coins are multiplied by 100, into an integer, the input data also do the same processing, and then is a set of complete backpack template, in the output of the format and precision to card a card yo
Finally on the UVA AC 50 questions, feel there is a long way to go!!!It's a bit of a problem, or it's written in STL.1#include 2#include 3#include 4#include Set>5#include 6 using namespacestd;7 Const intmaxx=1010;8typedefstructNode9 {Ten stringBook,name; One BOOL operatorConst structNode x)Const A { - if(Name!=x.name)returnnameX.name; - returnbookX.book; the } - }node; - intMain () - { + //freopen ("In.txt", "R", st
UVA 11624 fire! Topic: J Work in the Maze, one day The Maze fire, the fire has many places. Every second, the fire will spread to four directions, J will also move to four directions, asked J can run out, to output him to run out of the shortest time, otherwise output "impossible" problem-solving ideas: first to carry out a BFS, find every point of flame spread to the shortest time of the place. Then, according to the "Fire map", the path of J is BFS.
Topic Portal1 /*2 Test instructions: To change the minimum number of 0 1, so that each element around the and is an even3 enumeration: Enumerates all possible (14 finally check the different quantity, take the minimum value5 */6#include 7#include 8#include 9 using namespacestd;Ten One Const intMAXN = -; A Const intINF =0x3f3f3f3f; - intA[MAXN][MAXN], B[MAXN][MAXN]; - intN; the - intCheckints) { -memset (b,0,sizeof(b)); - for(intI=0; ii) { + if(S (10][i] =1; - Else if(a[0]
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