uva timecard

Portal View As the timecard list increases, how to find and manage many timecard becomes a problem. Especially for a team manager, in addition to the timecard he entered, he also needs to review the timecard tasks of team members. Here I want to simplify the actual requirements into two main views (but the results are

Now, you can analyze a little data based on the timecard data. Application Requirements For timecard, the following two aspects are analyzed: For a single project, analyze the labor ratio of each Member to understand the workload allocation and provide reference for inter-group personnel scheduling. For the entire company, analyze the change trend of timecard's total working hours every week to understan

To give you a mobile phone version of nails users to detailed analysis to share the use of clocking out. Method Sharing: 1, use the smartphone to download and install the mobile software, and then to register, add a group of companies,

UVA 10047 UVA Live 2035 bfs//for the shortest, must first try BFS//Determine the state, the first state must have coordinates x,y//also have to have direction, there must be a color value/////This is a state there are three kinds of attributes//each state as long as the experience, and then Experience doesn't make any sense.//Use an array of que thoughts to record on the line. In accordance with the directi

Links:http://acm.hust.edu.cn/vjudge/problem/viewProblem.action?id=20837http://acm.hust.edu.cn/vjudge/problem/viewProblem.action?id=21278Ask for a bare question on the top of the cut.UVA-315#include UVA-10199#include UVA-315 Network and UVA-10199 (for cutting top)

graph and there is no singularity vertex in the graphPrint the word from any point of departure, recursive output Path = =#include #includestring.h>#include#include#include#include#includeusing namespacestd;Const intmaxn= -;intMP[MAXN][MAXN];intp[ -];intdir[ -];intF[MAXN];intN;structnode{intu,v;};voidinit () { for(intI=1; i -; i++) P[i]=i;}intFindintx) { returnP[x]==x?X:find (p[x]);}voidDfsintu) { intv; for(v=1; v -; v++) { if(mp[u][v]>0) {Mp[u][v]--; Mp[v][u]--; DFS

? means the scaanf and cin of the flapping street. ② then it entered the instruction is infinite and then to 0 end, well this is still relatively easy but actually the command in the middle there will be empty line ah I go ... There may be more than one line of instructions, what does a blank line mean? It means that getline also jumped on the street. ③ Fortunately we also have C=getchar () while loop, but the output data also has the first regular pit is the letter finally can not have the extr

is a more complex simulation problem. There are two kinds of queues, one is the Corps column, the former is backward. The others are small queues for each group, because if the team members have teammates, they will get priority in the group queue. So let's set up two queues and a map, and setting up a map does not have to worry about how many arrays to open. Then open two queues, one is the basic Q1, the other is q2[1010] general STL container such as String vector deque are two methods of dire

UVA-10603-Fill (BFS + priority queue), uva-10603-fillbfs There are three jugs with a volume of a, B and c liters. (a, B, and c are positive integers not greater than 200 ). the first and the second jug are initially empty, while the third Is completely filled with water. it is allowed to pour water from one jug into another until either the first one is empty or the second one is full. this operation can be

UVa-1585 Score (Score), uva-1585score Score Hello world! Celebrate the first official blog! UVa-1585 Score Question stem: Give a string (length) consisting of O and X, and calculate the score. Each O score is the number of consecutive O Records, and X scores are 0. For example, the OOXXOXXOOO score is 1 + 2 + 0 + 0 + 1 + 0 + 0 + 1 + 2 + 3. Input Format: read data

note is that the recursive DP when the three rectangles are in the lower right corner (because the number of bars is unchanged because of the downward or right translation of a unit), so that if the recursion is to consider from this point to (I,J) this point of the situation can be, while the recursive ans, The rectangle is the upper left side, then, as long as the entire large rectangle inside to (i,j) this point of the situation can be. Of course, purely personal understanding.UVA 1393 Highw

); - - for(inti =1; I i) { +scanf"%s", p[i].ch); - + intA =strlen (p[i].ch); A at for(intj =0; J j) { -P[i].ch[j + A] =P[i].ch[j]; - } - - stringMin ="zzzzzzzzzzzzzzzz"; - in for(intj =0; J j) { - intK = j + A-1; to strings; + - for(intg = J;g g) thes + =P[i].ch[g]; * //cout $ if(S min) {Panax NotoginsengMin =s; - //cout the } +

UVA 725Test Instructions: 0~9 10 number consists of two 5 digits (or four digits beginning with 0), which requires that the quotient of two numbers equals the input data n. Abcde/fghij=n. Idea: Violent enumeration, enumeration of FGHIJ cases to calculate whether the ABCDE to meet the conditions of the problem. (Note the decision of leading zeros) The enumeration method is for (int i=1234;i#include #includeintnum[Ten];BOOLCheckintAintb) {memset (num,0,

[i]--;c[i+1]--;c[i+2]--; + if(Search (dep+1))return true; Ac[i]++;c[i+1]++;c[i+2]++; the } + return false; - } $ $ BOOLCheck () - { - for(intI=0;i the; i++)//Enumerate the cards the if(c[i]>=2) - {Wuyic[i]-=2; the if(Search (0))return true; -c[i]+=2; Wu } - return false; About } $ - intMain () - { - intcasen=0; A intmj[ the]; + Chars[ -]; the BOOLOK; - while(cin>>s) $ { the if(s[0]=='0') Break

The main need of recursive function calculation1 #defineMAXN 60+102 3#include 4 using namespacestd;5 6 intN,K,S[MAXN],F[MAXN];7 8 Long LongFint*p,intIintfinal)9 {Ten if(i==0)return 0; One if(p[i]==final)returnF (p,i-1, final); A returnF (p,i-1,6-p[i]-final) + (1ll1)); - } - the intMain () - { - intKcase=0; - while(cin>>N) + { - if(n==0) Break; + for(intI=1; iS[i]; A for(intI=1; iF[i]; atk=N; - while(k>=1AMP;AMP;S[K]==F[K]) k--; -

Few points, sort by edge weights, enumerate enumerations L and R, check connectivity. Once connected, update the answer.Judge even General can O (1), before I was O (n) sentenced, previously written over, and later wrote T ... #include using namespacestd;Const intMAXN =101;Const intMaxe = maxn*maxn>>1;intn,m;intU[maxe],v[maxe],w[maxe];intPa[maxn];inlineBOOLcmpintAintb) {returnw[a]w[b];}intR[maxe];inlinevoidIdxsort () { for(inti =0; I i; Sort (R,r+m,cmp);}intFind (intx) {returnx==pa[x]?x:pa[x]=Fi

Uva--uva 10201Adventures in Moving-part IV

tree to get the number of white edge limit, and then determine if there are no fib number in this interval, the first time we take the black edge of the main sort to find the minimum spanning tree, to get the white edge number of the lower limit, The maximum number of white edges is obtained by the minimum spanning tree with the white edge as the main sort. Note If the first diagram is not connected, then output No. The code is as follows: #include G-slim Span (

[2016-02-19] [UVA] [524] [Prime Ring problem] UVA-524Prime Ring problem Time Limit: 3000MS Memory Limit: Unknown 64bit IO Format: %lld %llu Submit StatusDescriptionA Ring is composed of n (even number) circles as shown in diagram. Put natural numbers into each circle separately, and the sum of numbers i

Uva-11538chess Queen Test instructions: The number of scenarios in which the n*m placed two attacks against each otherSeparate discussion rows and columns two diagonal linesA sum-up Can be simplified after the calculation of////main.cpp//uva11538////Created by Candy on 24/10/2016.//copyright©2016 Candy. All rights reserved.//#include#include#include#include#includeusing namespaceStd;typedefLong Longll;inline ll Read () {CharC