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do not know whether test instructions some details did not understand, or some special picture of the situation did not take into account. Use this idea even though the code is more refined. But always WAThen simply put all the vertices in the determinant, and then seek the edge. Think about it a little bit to know that the number of edges is based on the number of tracks added to the middle of the trajectory, that is, on the trajectory. Number of intersections not in track two pointsHere it is

UVA 624 CDYou had a long drive by car ahead. You had a tape recorder, but the unfortunately your best music was on CDs. You need to has it on tapes so the problem to solve is:you has a tape N minutes long. How to choose tracks from CD to get the most out of tape space and has as short unused space as possible.Assumptions:Program should find the set of tracks which fills the tape best and print it in the same sequence as the tracks is stored On the CDI

UVa 1225The main idea: to write the first n (nProblem-solving ideas: Using a CNT array to record 0-9 of the number of occurrences of the 10, first to initialize CNT to 0, and then let I from 1 to enumerate to N,For each I, the number of each position that is treated with live I, and the corresponding CNT subscript on +1The final output of the CNT array can/*UVa 1225 Digit Counting---water problem*/#include#

UVA 11551-experienced EndeavourTopic linksTest instructions: Given a column number, each number corresponds to a transform. The sum of the positions added to the original sequence, and the number of times after the R transformation.Idea: Matrix high-speed power, to add the position value of 1. The remaining position is 0 constructs the matrix, carries on the high speed power to be possibleCode:#include UVA

1 /*UVa 11292 Dragon of Loowater*/2#include 3#include 4#include 5#include 6 using namespacestd;7 intn,m;8 intMain () {9 while(SCANF ("%d%d", n,m) n!=0 m!=0){Ten inti; One inta[20050]={0};//Faucet diameter A intp[20050]={0};//Knight Power - for(i=1; i"%d",a[i]); - for(i=1; i"%d",p[i]); theSort (A +1, a+n+1); Sort (p+1, p+m+1); - intnum=1; - intsum=0; - for(i=1; i){ + i

UVA 1306 the K-leagueDescriptionSupporters for the professional soccer clubs participating in the K-league, formerly the Korea Professional Soccer League, Hold orderly and organized cheering, as do the Red Devils, the official supporters for the Korean national soccer team D Uring the 2002 Korea-japan World Cup. After many games of this season has been played, the supporters may wonder whether the team S they is backing can still Win the championship.

UVA 165 StampsThe government of Nova Mareterrania requires that various legal documents has stamps attached to them so, the GOVERNM Ent can derive revenue from them. In terms of recent legislation, each class of document was limited in the number of stamps that may was attached to it. The Government wishes to know about many different stamps, and of what values, they need to print to allow the widest choice of values to is made up under these conditio

UVA 993 Product of digitsTopic: Given a number n, requires a number, so that the number of each bit will be equal to N, and the value of the number is the smallest.Problem solving: A simple decomposition factor. Note that there are two points: 1) factor from 9 to 2 times, can guarantee the minimum number of bits, 2) when n equals 1 is the best special treatment.#include UVA 993 Product of digits (decomposit

UVA 10718 Bit MaskIn bit-wise expression, mask was a common term. You can get a certain bit-pattern using mask. For example, if your want to make first 4 bits of a 32-bit number zero, you can use 0XFFFFFFF0 as mask and perform a bit-wi SE and operation. Here are the such a bit-mask to find.Consider you given a 32-bit unsigned integerN. You had to find a mask M such that l≤m≤u and N OR m is maximum. For example, ifn is and L = A, U = $ thenM would be,

UVA 1401-remember the Word[Topic link]Test instructions: given some words. and a long string. Ask this long string split into existing words, can split into several waysTrain of thought: Trie, the word is built Trie first. Then the DP. Dp[i] Indicates a case that begins with I, and then each state simply finds the corresponding I-beginning word on the trie tree, then dp[i] = Sum{dp[i + len]} for state transfer toCode: #include

Thinking about it:The title is somewhat similar to the eight queens, but there is no limit in the direction of the diagonal, but a more restricted area. Because the problem of n max up to 5000, dare not rashly use backtracking. It can be learned that each rook in the title area is a rectangle, and each in the display, the x, Y axis is actually independent of each other, how to place the x-axis position does not affect the y-axis. So you can put the x-axis position, and then place the y-axis posi

https://vjudge.net/problem/UVA-12325Test instructions: There is a box with a volume of N and two infinite treasures. The volume of the Treasure 1 is S1, the value of V1 ' Treasure 2 of the volume of S2, the value of V2. Calculate the maximum amount of valuable treasures to be loaded.The idea: The topic is very clear is the violent enumeration, but if does not simplify the enumeration the words certainly will be timed out, if N/S1 is smaller, then enum

https://vjudge.net/problem/UVA-12108Test instructions: Given the "Awake-sleep" cycle and the initial point of time for N students, each student needs to determine whether the number of people sleeping in the class is more stringent than the number of sober people during sleep, or else to judge after insisting on a sober cycle. Find out how long the whole class is awake.Idea: Water problem bar. Over and over again, the condition of the loop termination

Title Link: https://uva.onlinejudge.org/index.php?option=com_onlinejudgeitemid=8page=show_problem problem=666/*UVA 725 Division---Simple enumeration*/#include#includeBOOLused[Ten];/*determine if the two numbers passed in will meet the conditions*/BOOLJudgeintAintb) { if(A >98765) return 0; memset (Used,0,sizeofused); if(b 10000) used[0] =1; while(b) {used[b%Ten] =1; b/=Ten; } while(a) {Used[a%Ten] =1; A/=Ten; } intsum =0; for(inti =

Topic Link: UVA 10627-infinite RaceThe main topic: a certain way. Two people go back and forth on this road to find the number of encountersProblem-solving ideas: There are two kinds of encounters, one is chase, one is relative Pursuit:T ?(u?v)=(2?k +1)?L Relative:T ?(u+v)=(2?k +1)?L But there is a special case. It is to be considered two times when the boundary is met, so it should be lost once.So how to consider the time when the boundar

UVA 10251#include 2#include 3#include 4#include 5#include 6#include Set>7#include string>8#include 9#include Ten#include One#include A -#include -#include the - - #defineLson l,m,rt - #defineRson m+1,r,rt + -typedefLong Longll; + using namespacestd; A at Const intINF =0x7f7f7f7f; - Const DoublePI = ACOs (-1.0); - Const intMAXN =100005; - #defineLOCAL 0 - #defineMOD 1000000007 - in - intn,t; to intL,r; + intls[ -],rs[ -]; - inttimecost[ -]

UVA 1424-salesmenGive a picture, and give the path that NHN traversed, the path may be wrong, ask at least modify several places can make the path is correct.DP[I][J] Indicates the minimum number of modifications to the first I position where the I position is a J point.Dp[i][j] = min (Dp[i-1][k] + (j = = A[i])); {W[k][j] = = True exists path K~j}Then find a minimum value at the last point.#include #include #include #include using namespace STD;Const

J-Productcrawling in process ...crawling failedTime limit:MS Memory Limit:0KB 64bit IO Format:%lld %llu SubmitStatus Description Product The problemThe problem is to multiply, integers X, Y. (0)The InputThe input would consist of a set of pairs of lines. Each line in pair contains one multiplyer.The OutputFor each input pair of lines the output line should consist one integer the product.Sample Input12122222222222222222222222222Sample Output1

Finally on the UVA see a short topic, happy. After reading the topic, I was ignorant. Then you find the rules ...Find each line represents a letter, and then I start from a a control, write him out. Then a certain pattern was found: the important positions of each line were made up of ' o ' and '-', and a few of them found exactly 7, and then they thought of the Andean Code. Sure enough, the first one represents 2^6, the second represents 2^5, and so

UVA-10954ADD All Time Limit: 3000MS Memory Limit: Unknown 64bit IO Format: %lld %llu Submit StatusDescriptionProblem FADD AllInput: standard inputoutput: standard outputyup!! The problem name reflects your task; Just add a set of numbers. But the feel yourselves condescended, to write a C + + program just to add a set of numbers. Such a problem would simply question your eruditio