How to calculate the period-over-period ratio of an SQL statement! The number of resumes in this month minus the number of resumes in the previous month () [number of resumes in this month]-[number of resumes in the previous month] = [number of
"Number of resumes in the month"-"resumes last month" = "Number of years" ()
How is the SQL statement written?
SELECT date_format (m_adddate, '%m ') as Month,count (m_id) as Zong,date_format (m_adddate, '%Y ') as year from Job_myreceive where Date_
1.get the first day and last day of the month.echo Date (' y-m-01 ', Strtotime ('-1 month '));echo "";echo Date (' Y-m-t ', Strtotime ('-1 month '));echo "";2.get the first day of the month and the last day.$BeginDate =date (' y-m-01 ', Strtotime
Bat obtains the previous month.If you want to back up the last month's files at the beginning of each month, you need to obtain the last month's Month. Note that the last month of July is July, in addition, the result of reducing the number by 1 for
Select Year (payment_date), sum (Case month (payment_date) When 01 then amount end) 'sale in February ', sum (Case month (payment_date) When 02 then amount end) 'October sales', sum (Case month (payment_date) When 03 then amount end) 'October sales',
Tags: datepart function SQL used date month year grouping group by group 2013-12-26 15:31 20764 People read reviews (1) Favorite report Category: SQL Server (21) Copyright notice: This article for Bo Master original article, not allowed to reprint
onTo say there is an article table article, the time to store an article's added article is the Add_time field, which is an int (5) type, you now need to query the total number of articles added today and sort by time from large to small, then the
Calculate the SQL statement of the last day of the last month of the given date.
Calculate the SQL statement of the last day of the last month of the given date.
Calculate the SQL statement of the last day of the last month of the given date.
DECLARE @date datetimeSet @date =getdate ()--the first day of the current month minus the daySelect DATEADD (Day,-1,dateadd (Month,datediff (month,0, @date), 0)) as ' last day of last month '--Another algorithm for the first day of the current
I. Annual ENQUIRY Enquiry data for the yearSELECT * fromblog_articleWHERE Year(From_unixtime (Blogcreatetime))= Year(Curdate ()) Second, query quarterly data query data with quarter numberSELECTArticleID, Quarter (from_unixtime (' Blogcreatetime ')
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