disk, in some necessary occasions can be used to destroy data. After you do this, the/dev/sda1 cannot be mounted, and the Create and copy operations cannot be performed.
Get the most appropriate block size:Dd?if=/dev/zero?bs=1024?count=1000000of=/root/1gb.filedd?if=/dev/zero?bs=2048?count=500000of=/root/1gb.filedd? If=/dev/zero?bs=4096?count=250000of=/root/1gb.file
By comparing the command execution time shown in the output of the DD inst
As with Fdisk creating an MBR partition, Sgdisk is a tool to create a GPT partition, and if you do not yet understand the GPT partition, refer to the difference between booting MBR and GPT with GRUB.View all GPT partitions# sgdisk -p /dev/sdbDisk /dev/sdb: 16780288 sectors, 8.0 GiBLogical sector size: 512 bytesDisk identifier (GUID): 4D5B29E8-6E0B-45DA-8E52-A21910E74479Partition table holds up to 128 entriesFirst usable sector is 34, last usable sector is 16780254Partitions will be aligned on
) */
#define EXP_15 2037/* 1/EXP (5sec/15min) */
The three constants represent constants of 1/5/15 minutes, respectively, and are calculated by:
1884 = 2048/(Power (E, (5/(60*1)))/*/E = 2.71828 */
= 2048/(Power (E, (5/(60*5))))
2037 = 2048/(Power (E, (5/(60*15))))
We assume that the previous time the load calculated as constant 1884 is load1 (t-1), the curre
have been doing the LTE physical layer related work, there has been a doubt, in 36.211 the beginning of a chapter defines the size of TS is 1/(15000*2048) s, why define so a strange unit time.Recently, this was related to the FFT/IFFT process.Assuming 20MHz bandwidth, the standard specifies that we use 2048 points to do the FFT process, the FFT process is the time domain, each time domain symbol has
--getioopt get optimal I/O size
--getalignoff get alignment offset
--getmaxsect get max sectors per request
--getbsz get blocksize
--setbsz BLOCKSIZE set blocksize on file descriptor opening the block device
--getsize get 32-bit sector count
--getsize64 get size in bytes
--setra READAHEAD set readahead
--getra get readahead
--setfra FSREADAHEAD set filesystem readahead
--getfra get filesystem readahead
--flushbufs flush buffers
--rereadpt reread partition table
View t
absrtact: The developer's enthusiasm for Swift has never diminished, and has been the emergence of a variety of outstanding open source projects. This time, we also hold "alone Lele not as many Lele" mentality, sharing a few use swift language development of ultra-practical applications, which also includes everyone's favorite 2048, lightweight chat applications.Since its release to the present, the developer's passion for Swift has never diminished,
ElGamal (default)(2) DSA (for signature only)(5) RSA (for signature only)What's your choice? [Enter] The DSA key pair will have 1024 bits.The ELG-E key length should be between 1024 bits and 4,096 bits.How big a key size do you want to use? (2048) [Enter] The key size you require is 2048-bitPlease set the validity period of this key.0 = key never Expires= key expires in n daysW = key expires after n weeksm
because the hard disk has only 64byte bytes to access the partition table, and each partition requires 16bytes, a hard disk can have up to 4 primary partitions. To break the limit of 4 partitions, the hard disk can be divided into 3 primary partition +1 extension (n logical partition)
Linux file System Management
Linux File system: EXT2,EXT3,EXT4,XFS,SWAP,BTRFS,REISERFS,JFS
Swap: Swap partition
Depending on whether the "jo
alignment 2048 or 4096.
4k alignment what meaning solid state hard disk 4k to alignment 2048 or 4096
The article finally simple popular science What do you mean by SSD 4K alignment, when you are working on a solid-state hard disk 4K alignment, choose 2048 or 4096 alignment.
What does 4K alignment mean?
4k alignment is a professional term in a har
very small block too large, the remaining space is wasted, can not continue to be used by other files.8) block is not the bigger the better, according to the size of the business file selection, is generally the default 4k.9) You can change the size of the Inode and block when formatting, using Mkfs.ext4-b 2048-i 1024/DEV/SDB2650) this.width=650; "Src=" Http://s5.51cto.com/wyfs02/M01/82/23/wKiom1dMSqnRBvnMAABPsZruOSo170.jpg-wh_500x0-wm_3 -wmp_4-s_156
very small block too large, the remaining space is wasted, can not continue to be used by other files.8) block is not the bigger the better, according to the size of the business file selection, is generally the default 4k.9) You can change the size of the Inode and block when formatting, using Mkfs.ext4-b 2048-i 1024/DEV/SDB2650) this.width=650; "Src=" Http://s5.51cto.com/wyfs02/M01/82/23/wKiom1dMSqnRBvnMAABPsZruOSo170.jpg-wh_500x0-wm_3 -wmp_4-s_156
Linux hardware devices in the/dev directory, the optical drive is one of them./dev/cdrom represents the optical drive, the method of mounting the optical drive is as follows (in root):
Copy Code code as follows:
Mkdir/mnt/cdrom
Mount-t auto-o ro/dev/cdrom/mnt/cdrom #不加参数也能自动挂上.
The following is a screen copy of the action:
Copy Code code as follows:
linux@cdyemail:/$ Ls/mnt #查看mnt下面有没有cdrom目录, this is a random catalogue.
CDROM ISO USB winc wind
linux@cd
following:
If the end position is removed, the server returns the last available byte of content from the beginning of the declaration to the end of the entire content.
If the start position is removed, the end position parameter can be described as the number of bytes that can be returned by the server from the last available byte.
Content-range: Number of bytes (bytes) = (start)-(end)/(total)
This header will be followed by the HTTP status code 2,061. The start and end values
system is started. Therefore, after the root user password is entered, You can restart fdisk sdb.
Then, the sdb 10.7 GB is partitioned into sdb1, the raw device is partitioned into sdc1, and then mkfs. ext3/dev/sdb1 is formatted.
In this way, the system is accessed, and the connection of/etc/sysconfig/rawdevices is modified.
After restarting the system again, it is found that DD can back up/DEV/RAW/RAW1 and no error is reported.
[Root @ node1 tmp] # dd if =/dev/zero of =/dev/raw/raw1 bs = 5
The virtual network card is defined by the-net NIC# qemu-system-x86_64-enable-kvm-name ubuntutest-m 2048-hda ubuntutest.img-vnc:19-net NICIf we view the info network in monitorYou can see the followingSometimes, we see VLAN 0, where the VLAN and 802.1.q a little relationship, is the concept of virtual hub, in the new version has been changed.We can do it in monitor.Set_link e1000.0 offSet_link e1000.0 onTo start and stop the network card-net nic [, VL
played , so the Sample_data event is immediately triggered . So we're going to add a listener function : function Onsampledata (se:sampledataevent): void{} Next add some sound data to this sound object to play sampledataevent there is a binary data" property bytearray.float method -1.0 to 1.0 Span lang= "en-us" xml:lang= "en-us". At this point the binary variable is set to each float value is commonly said sample 2048 and 8192.
Reprinted from: http://www.ityran.com/archives/3775
In principle, the cocos2d-x can display any size texture, but in fact the texture size is limited by hardware and operating system reasons.
Here we provide a table with texture size restrictions on different platform Simulators
Platform
Maxsize in pixels
Win32
2048*2048
Android
4096*4096
IPhone 3
1024*1024
IOS development-game screen adaptation (SpriteKit)
When we develop an App, we usually want it to run simultaneously on the iPhone, iPad, and Mac, especially games.
In this way, we need to consider the different resolutions of different devices, which is troublesome to process.
For example, according to the official practice, we need to provide such as xx.png, xx@2x.png, xx@3x.png, xx ~ IPad.png, and xx ~ Different pictures like iPad@2x.png,
In addition, it is annoying to write a large number of
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