x86 assembly instructions

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Several basic assembly instructions

Several basic assembly instructions in detail common registers Register Device 16 Guests 32 Guests 64 Guests Cumulative register Ax EAX RAX Base Address Register Bx EBX RBX Count Register CX Ecx RCX Data registers Dx EDX Rdx Stack base

"Assembly Instructions" arm instruction set register and 32-bit overview

(status bit)N: Negative when n = 1, n = 0 for integer or zeroControl bits:1) Interrupt Disable bit: when I or F = 1 o'clock, indicates interrupt binary2) Status control bit: When t = 0 indicates in arm state3) mode control bit: MODE (Below is binary) 10000 User mode Pc,cpsr,r0~r14 10001 FIQ Pc,cpsr,spsr_fiq,r14_fiq~r8_fiq,r7~r0 10010 Irq Pc,cpsr,spsr_irq,r14_irq~r13_irq,r12~r0 10011 Manageme

Assembly language Note call and RET instructions

entering subroutines, the top of the stack holds the IP, followed by a, B 3; Result: (Dx:ax) = (A-B) ^3 4 difcube:push BP 5 mov bp, SP 6 mov ax, [bp+4]; the value of a in the stack is fed into AX 7 Sub Ax, [bp+6]; A-B 8 mov bp, ax 9 mul bp10 mul bp11 pop BP12 ret 4 ; Popup parameter (modify the top pointer to the value before the call) 13 14; The meaning of the directive ret N: 15; Pop ip16; The Add sp,n uses the stack for parameter passing, so the caller pres

Some assembly instructions (based on 8086)

= The address of the first byte after the address-call instruction at the "label";The range of 16-bit displacement is -32768~32767, which is indicated by complement;16-bit displacement is calculated by the compiler at compile timeCall is equivalent to:Push IPJMP near PTR labelCall far PTR designator:(1) (sp) = (sp) –2((ss) x16+ (sp)) = (CS)(sp) = (sp) –2((ss) x16+ (sp)) = (IP)(2) (CS) = segment address where the label is located(IP) = offset address where the label is locatedEquivalent to:Push

"Assembly language" summary 02--[BX] and loop instructions

are all referred to as segment prefixes.A safe space:In a normal PC, DOS and other legitimate programs do not generally use the 0:200~0:2FF 256-byte space, so we call this space safe.Use of segment prefixes:650) this.width=650; "title=" 0.png "alt=" wkiom1j4pf6ysx67aab9yxilb7a167.png-wh_50 "src=" https://s5.51cto.com/ Wyfs02/m01/91/c4/wkiom1j4pf6ysx67aab9yxilb7a167.png-wh_500x0-wm_3-wmp_4-s_3553888335.png "/>Summary complete!This article is from the "where No Play" blog, please be sure to keep

Introduction to assembly instructions

1.TEST Logic comparison, the directive in a certain program and CMP instruction similar, two numeric values and operation, the results are not saved, but will change the corresponding flag (for example, SF,ZF,PF flag), the program can decide whether to jump to the corresponding branch. Here are a few examples: TEST eax,eax. Would you say that if eax compared with himself? With this command, you can determine whether EAX equals 0.JMP – Jump JE, JZ – The result is zero then jump JNE, JN Z – The r

Yjx_rxjh_ Assembly Instructions

1, 3.1.2"12:26" "Repne scas" command (ZC: Default is EAX, ECX)"18:42" "REP MOVS BYTE ptr es:[edi], DWORD ptr Ds:[esi]""REP MOVS byte ptr es:[edi], byte ptr Ds:[esi]""19:08" REP MOVS ==> performs a copy operation of a string"19:12" Repne SCAS ==> Search to the end of the string (0 where two exits the loop condition: The value of ECX is 0 or the location where the value is eax is found)"22:40" Repne SCAS Locate the value in the string Al that the EDI points to, count in ECX (not ECX take the inver

ARM assembly Instructions MCR/MRC Learning

The MCR instruction arm data register is transmitted to the coprocessor register. Assume that the coprocessor cannot run the operation successfully. An undefined instruction abort is generated.Grammar teaching Format:Mcr{MCR2 P15, 0, Of For the CP15 coprocessor, The MRC instruction transfers the value of the coprocessor's registers to the registers of the ARM processor. Assuming that the coprocessor does not successfully run the operation, it will result in an abnormally broken instruction witho

Assembly language--[BX] and loop instructions

StartThe right1AssumeCS:Code2 Code Segment3 Start: movAx,0ffffh;The compiler does not support the beginning of a letter4 movDs,ax5 movBx06 movDx07 movCx A8 9 S:movAL,[BX];assign value to lowTen movAh0 One AddDx,ax;add with 16 bits so that it does not overflow A IncBX - Loop S - the movax,4c00h - int + - code ends -End StartSegment PrefixThe "DS:", "CS:", "SS:", or "es:" that appear in the instruction that accesses the memory u

Assembly language: The fifth Chapter [BX] and loop instructions

Cs:codeCode segmentMOV ax,2MOV cx,11S:add Ax,axLoop sCode endsEnd5.3 Tracking the Loop command with debugDebug 1.exe-R-T-T..-P (int 21H is performed with P)1. If you want to jump directly to the cs:xx position, execute with-G XX2. If you want to jump in the loop, that is, stop waiting for-t after the loop, use the-p command5.4 Debug and assembler compiler for different processing of instructionsSame instruction:MOV ax,[0] In debug means to put ds:0 and Ds:1 memory unit contents into AXIn the MA

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