xserve 2009

Title Link: BZOJ-2463Problem analysisThe solution to this problem is that since both of them take the optimal strategy, all the squares will eventually be taken. (why.. I don't know what to say. Which God Ben can tell me about Qaq)So.. It becomes the parity of judging n*n, which is to judge the parity of N.Code#include 　　[BZOJ-2463] [Zhongshan 2009] who can win? "Game Theory" "

) = 1/2-1/2*2/3 = 1/2 * (1-2/3) = 1/2*1/3 = 1/6 I don't need to talk about the four books. The distance from the center of gravity of the four books to the left endpoint of the fourth book The center of gravity of the first book is: 1/6 + 1/4 + 1/2 + 1/2 The second book focuses on: 1/6 + 1/4 + 1/2 The center of gravity of the third book is: 1/6 + 1/2 The center of gravity of the fourth book is: 1/2 So the focus of the four books is (1/6*3 + 1/4*2 + 1/2 + 1/2*4)/4 = 1/2*3/4 + 1/2 A [4] = 1-(1/2*

Maintain a sequence, and be able to add and multiply intervals. Then, take the values of the range and the modulo number. Idea: The line segment tree maintains a tag with two domains, one representing addition and the other representing multiplication. When downloading data, add the following parameters first. Code: #include Bzoj 1798 ahoi 2009 maintains sequence seq

There is a color segment with a length of n. There are m colors in total. You need to divide it into several segments, and the cost of each segment is the square of the number of different colors in this segment. Calculate the minimum total cost. SOL: First, we noticed that the answer should not exceed n, because we can clearly divide each one into a segment and the answer is N. Therefore, the total color of each segment cannot exceed SQRT (n ). Therefore, we maintain the final position of the

[Question link] Https://www.lydsy.com/JudgeOnline/problem.php? Id = 1875 [Algorithm] Use F [I] [J] to show the number of solutions on the J edge while taking step I. Matrix acceleration. Time Complexity: O (N ^ 3 logn) [Code] #include [Sdoi 2009] HH for a walk

Question Surface Hall Theorem in Board Discussion Hall theorem: a bipartite graph has a perfect matching condition. For any $ I $ left vertex, there are at least $ I $ right vertex adjacent to them. Put it in this question, that is, it is obvious that the case that the shoes are not enough is a continuous person, so we can maintain the maximum sub-section and just like =. = 1 #includeView code Solution: poi 2009 lyz

There are wolves and sheep in a farm. Now I want to separate them with fences and ask the minimum number of fences required. Train of Thought: All sources are connected to all wolves, and all sheep are connected to one edge. In the figure, each adjacent grid is connected to one edge, and then the S-> T maximum flow is run, that is, the minimum cut between a wolf and a sheep. Code: #include Bzoj 1412 zjoi 2009 the story of the wolf and the sheep

Description Considering that N is large and M is small, you can use the merge tree, build and pre-process interval answer O (nlogn) If a number appears more than half in the interval, at least half of the number appears in a subinterval, Find the number of occurrences in the subinterval over half of each query and check the occurrences in the total interval. The complexity of a single query is O (log3n) #include Bzoj2223 [coci 2009] patuljci

Label: style blog Io color ar SP strong data Div Description: There are two dates. Calculate the number of days between two dates. If two dates are consecutive, we specify the number of days between them as two days. Input: There are multiple groups of data, each of which has two rows, representing two dates, in the form of yyyymmdd Output: Output a row of data in each group, that is, the date difference.

Label: bzoj spfa Here is a map with obstacles on some points. Now there is a t chance to remove the obstacle and ask how long is the longest Euclidean distance on the map. Idea: create an image based on the source image. f [I] indicates the minimum number of obstacles to be removed from the start point. Then, use brute force enumeration to start the source point and update the answer. Code: #include Bzoj 1295 scoi 2009 longest dist

Morning News recently, anti-virus software company Rising officially launched the "Rising Full functional security software 2009", the boxed product integration, "interception, defense, killing, protection" and other multiple protection functions, its upgrade service period of up to 3 years, but the official recommended retail price but 299 yuan. It is understood that the general official retail price in 299 yuan of products, the final price of most o

Title Link: http://www.lydsy.com:808/JudgeOnline/problem.php?id=1565Orz topic too god ... Knees have been kneeling ....This problem requires us to establish a complex protective relationship between plants and plants, as well as the loss and reward of eating plants, so we have to use the maximum flow, modeling is amazing, kneeling on your knees ...First we establish source and sink points, and for each plant, if it can get energy, it has an edge between the source point and it, and the capacity

Operating system: WINDOWS.SERVER.2003.R2,ENTERPRISE.EDITION,SP2,X86,CHS,VOL,MSDN This time configure the PHP server environment: windows2003+ iis6+php5+ Mysql3+zend+phpmyadmin The entire configuration process needs to be logged on to Windows using a System account with administrator privileges the screenshot shown throughout the configuration may vary depending on the system used, the window interface, However, the corresponding tab column is the same, only need to find the corresponding tab

[Coci 2009]patuljci DescriptionGive a sequence with n numbers, have an M query, ask each interval [l,r], whether there is a number of more than half, if present output this numberSample Input10 3 1 2 1 2 1 2 3 2 3 3 8 1 2 1 3 1 4 1 5 2 5 2 6 6 9 7-10Sample OutputNoYes 1NoYes 1NoYes 2NoYes 3HINTNotice: Enter a second integer that is the range of weights in the sequence Lim, that is, 11 Code #include

JSON (JavaScript Object notation) is similar to XML; It started with JavaScript and was supported by multiple languages, and it became one of the new features of Delphi 2009. If there is a section of XML: JSON is extremely convenient to use in JavaScript, such as: Example 1: Data = {"id":2, "name":"张三 ", "age":99}; str = Data.id;　　　//2 str = Data.name;　　//张三 str = Data["name"]; //张三 //Example 2: Data = {"id":2, "name":{"FirstName":"张 ", "LastName

often achieved is an up-and-comer. Do not know whether the meal has gone to where, to give a toast to it. Currently on the market, large and small microblogging products: Twitter (ancestor), Rice, Campus micro-blog, muttering (Fire rabbit), Tencent surging, Tencent broadcast (in the QQ mailbox), Sina Weibo, do what, 9911, classmate net, fresh fruit Network, NetEase Weibo, Crab Claw, Follow5, Lei Monkey, Guizhou Guest, drive cattle, Outside the net, Yahoo meme, Jaiku, Heart, lobbyist, half flow

Tqueue and Tstack, one is the list of queues, one is the stack list; One is advanced first out, one is advanced later out. Tstack has three main methods, one attribute: Push (press stack), Pop (out of Stack), Peek (see the next element to be out of the stack); Count (total elements). This example effect chart: Code files:Unit Unit1;InterfaceUsesWindows, Messages, sysutils, variants, Classes, Graphics, Controls, Forms,Dialogs, Stdctrls;TypeTForm1 = Class (Tform)Memo1:tmemo;Button1:tbutton;

member of the default zone is equivalent to the published area.Since Tpersistent (which is the ancestor of many classes) has already specified {$M +}, most of the classes are {$M +} open.{$M +}TClass2 = Classfunction fun2:string; {Default Zone}Privatefunction fun2private:string;Protectedfunction fun2protected:string;Publicfunction fun2public:string;Publishedfunction fun2published:string;End{$M-}The compiler directive Methodinfo is the Delphi 2009 new

(0 or 1) to meet the necessary parity conditions.(3) Make the required k parity check for the information received.(4) If all the parity check results are correct, the information is considered to be error-free. If one or more errors are found, the wrong bits are determined uniquely by the results of these checks.One of the basic considerations when seeking a sea-key is to determine the minimum number of check digits required K. Consider the information with a length of n bits, and if the K che

Happy 2009Time limit:3000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)Total submission (s): 2394 Accepted Submission (s): 802Problem Descriptionno matter you know me or not. Bless Happy in 2009.Inputthe input contains multiple test cases.Each test case included one string. There is made up of ' a '-' Z ' or blank. The length of string would not be large than 10000.Outputfor Each test case tell me how many times "happy" can be const