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the cross product: 1: The result is that A and B form the parallelogram area of the adjacent edge. 2: The result has a positive negative, there is a sin (a, b) and its angle, the angle is greater than 180 ° is negative. 3: Cross product does not meet the Exchange lawApplication: (1: Through the results of positive and negative judgment between the two vectors of the cis-counterclockwise relationship if a X B > 0 means a in the clockwise direction of b if a x B (2: Judge the zigzag turn, can be

= cin.nextint (); BigInteger ans = biginteger.one;for (int i = 1; I F-Calf re-warI am looking at the sample to guess, except that the number of 1 is all different or up to see if it is $0$. The reason is to study it in depth.#include G-Flood problem$ shaped pressure dp$.$DP [i]$ indicates that the number of digits divisible by the $i$ state can be divided by a few, and the number of digits that can be divisible by the state $i$ is calculated backwards, $DP [0]$ is the answer. Look at the code

It's mainly about rsync.On-Machine experimentand write some scripts.Here is the script for automatic backup#bak Site and logscd/var/html tar zcf/backup/www_$ (date +%f). tar.gz./wwwCd/app tar zcf/backup/logs_$ (date +%f). tar.gz./logs#bak SYS confCD/ tar zcf/backup/etc_$ (date +%f). tar.gz./scripts/bin/cp/var/spool/cron/root/backup/#rsync data to BakserverRsync-avzp/backup/rsync [Email protected]::backup/--password-file=/etc/Rsync.password#del data 7 days agoFind/backup-type f-name "*.tar.gz"-

Or is that sudo and su?When you log in with Su, add the following-Because of this, the environment variable will become the switch user'sThis can cause unnecessary trouble if you do not use environment variables.General Sudo is not allowed for remote logins, because passwords are plaintext and are very insecureBut you can use ssh-t [email protected] sudo-l this way to log inOkay, I'm done.20161129l04-09 old boy Linux OPS training-linux system user and

Sersync pressure test in the next sectionThis section focuses on the pressure test text of the previous section to do a real stress testTest out exactly what the sersync pressure limit is.From 10 to 100 per second# Tree |wc-l #查看写了多少文件# uptime #查看负载Here is the test script#!/bin/shcount=100While TrueDoFor ((i=1;iDo/BIN/CP 10k.jpg/backup/test/$i/10k_echo $ (date) $RANDOM |md5sum |cut-c 1-8.jpgDoneSleep 1For ((i=1;iDo/BIN/CP 30k.jpg/backup/test/$i/10k_echo $ (date) $RANDOM |md5sum |cut-c 1-8.jpgDon

precision.4. Startup script location for all services/ETC/INIT.D5, Uname-r U is worth the Unixname kernel version. This command can be used to view the actual kernel version.6, CD switch directory. Changedirectory's abbreviation.7. The directory where PWD prints. Printworking Directory pwd-p Print non-linked addresses.8, mkdir-m This m refers to the umask user rights. You can use MKDIR-M 711 filename to force permissions on a file.9. Mkdir-p create a directory recursively.10. Cp-p is copied wit

(XL) Lt1-2The problem is still not very difficult, but note the operator overloads so that sort, as well as the construction members, and the sort encounter vector iterator.Wrote two copies of the code.Attach your own common method first:#include #include#includeusing namespacestd;Const intmaxn= ++5;structsoldier{intb; intJ; BOOL operatorConstSoldier a)Const{ returnJ>A.J; }}; Soldier A[MAXN];intMain () {intN,kase=0; while(SCANF ("%d", n) = =1N) { for(intI=0; i"%d%d",a[i].b,A[I].J

connected components. the necessary and sufficient condition of the binary graph is that there is no odd circle, which can be obviously obtained: if a two-connected component is a binary graph, then the inside point must not be on the odd circle. If a two-connected component is not a binary graph, will the dots in it be on the odd circle?The answer is certain in the odd circle, the first two connected components is not a binary map, then there must be a singular ring C. There are two states fo

Issue: To write a spiral phalanx. The spiral phalanx form is as follows:1 12 11 102 13 16 93 14 15 84 5 6 7Set Row,column to represent row, column coordinates, the variable p from 1 to N2 p in order to the array A[row][column], to determine the row, colomn changes. The analysis is as follows: Introduce the variable k, the initial value is N. When the data is deposited to the lower-left or upper-right corner, K minus 1, which guarantees the output matrix. The introduction of the variable T, the i

motion = = Uieventsubtype.motionshake { var alertController1 = Uialertcontroller (title: "Congratulations, you've succeeded!") ", Message:nil, Preferredstyle:. Alert) var cancelaction = uialertaction (title: "Cancel", Style:.) Cancel, Handler:nil) alertcontroller1.addaction (cancelaction) Self.presentviewcontroller ( AlertController1, Animated:true, Completion:nil) } }This method is judged at the end of motion, and if motion is shaking,

Shareview = Shareviewcontroller () Self.presentviewcontroller ( Shareview, Animated:true, Completion:nil) } @IBAction func message (Sender:uibutton) { if Self.cansendtext () {let Messagevc = Self.configuredmessagecomposeviewcontroller () Presentviewcontroller ( MESSAGEVC, Animated:true, Completion:nil) } else {let Erroralert = Uialertview (title: "Cannot send", message: "Your device is not short Function ", Delegate:self, Cancelbuttontitl

Sometimes we can not put all the content in a page, we need to use the ScrollView, the extra content is scroll to get.First define the width and height, easy to fit the equipment.Let PageWidth = PageHeight = 800Then initialize a scrollview in the viewdidload:var ScrollView = Uiscrollview () scrollview.frame = Self.view.bounds scrollview.contentsize=cgsizemake ( CGFloat (PageWidth), CGFloat (pageheight)) scrollview.pagingenabled = True Scrollview.showshorizo

Link to original topicDescribeSmall fish spit bubble, toot toot out. Small fish will spit out two kinds of bubbles: Big bubble "o", Small bubble "O".Two adjacent small bubbles will melt into a large bubble, two adjacent large bubbles will explode.(Yes, you're right, little bubbles and bubbles don't make any difference, and I don't know why.) ）Note: Merge from left to right.For example: Oooooooo will become OO after a period of time.InputThe data has multiple groups and is processed to the end of

1. The task class represents a thread, and the simplest task is constructed by a parameter of Action2. You can also use the Task.Factory.StartNew method, which constructs a Task and starts running immediately. Equivalent to executing the constructor of a task with the Start method.4. Task5. To suspend the current thread, wait for a thread to finish, you can use the Wait () method of the execution thread, and the wait method has some overloads that specify the wait timeThe results are several, in

1, When making a table, it should be a line of drawings, that is, H3> Test array initialization and operationH3>TableId= "Carname"Width= "120px"Border= "100px">Tr>Td>noTd>Td>1Td>Td>2Td>Td>3Td>Tr>Tr>Td>carnameTd>TdId= "First">aodiTD> td ID= "second">benchitd> TD ID = "Third">bydtd> tr> table> Execution resultsIf the 2, JS and CSS statements can be separated into files, and then linked to the HTML file.src= "Myscript.js">script> "stylesheet" href= "Test.css"/> 3. CSS Box model4, Vscode Chinese g

property value in the controller for $scope,$scope. Q = {Name: ' m '}With the code above, we can implement the function of dynamic filter collection.4. Custom FilterOf course, the built-in filter can not meet all your needs, then you can engage, how to do what you want to do, you want to.Usually we can use the module's filter method to define one. As follows:Module.filter (Filtername,function () {return function (Input) {return;}});Let's start with a filter to add a string! No.First declare a s

local variable, because each number of groups is stored differently. AC Code#include #includestring.h>#includeusing namespacestd;intMain () {intN; voidInitintN); while(~SCANF ("%d", N)) {init (n); printf ("\ n"); } return 0;}voidInitintN) { intnum; intI, j, K; inta[ +];//arrays are defined as local variablesnum =0; I=0; while(n) {J= n%2; //memset (A, 0, sizeof (a)); if(J = =1) {A[num+ +] = i;//Store the first few times is 1} i++; N/=2; } for(i = num-1; I >=0; i--) {

3#include 4 using namespacestd;5 inta[502]={0},b[502];6 voidcal () {7 inti,j,k;8memset (b,0,sizeof(b));9 for(i=1; i -; i++) {//corresponding multiplicationTen for(j=1, k=i;j -; j + +){ Oneb[k]=b[k]+a[i]*A[j]; Ak++; - if(i==501) Break;//take the No. 500 place on the break, the title requirements, no more useless. - } the } - for(i=1; i -; i++) {//Handling Rounding - if(b[i]>=Ten){ -b[i+1]+=b[i]/Ten; +b[i]=b[i]%Ten; - } +A[i]=b[i];/

One, blog:Second, edit the login interface Enter User name password Show welcome message after successful authentication Lock after entering three times Three, multi-level menu Level three Menu Select to go to the respective sub-menu Required Knowledge points: List, dictionary You can exit to the previous menu at any time Job Two:I wrote it by myself:#!/usr/bin/envpython#-*-coding=utf-8-*-#AUTHOR:d uwentaousername=[' Duwentao ', ' Liuxiaohui '] #存储

Python is a computer programming language, also known as glue language, can be used in a mixed compilation of C/c++/java and other languages such as libraries. You may have heard of many popular programming languages, such as C , which is very difficult to learn in college, a very popular Java Language in society, and Basic for beginners language, very suitable for the Java language of Web programming , and so on,Python is one of them. 1. website back-end programmer: use it as a single site, b