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Description: Say you have an array for whichITh element is the price of a given stock on dayI. If you were only permitted to complete at most one transaction (ie, buy one and every one share of the stock), design an algorithm to find the maximum profit. Solution: You only need to calculate whether the difference between the current value and the previous minimum value is greater than the maximum benefit. The following code is used: 1 class Solution {

Say you have an array for whichITh element is the price of a given stock on dayI. If you were only permitted to complete at most one transaction (ie, buy one and every one share of the stock), design an algorithm to find the maximum profit. The problem is abstracted to find the maximum difference value of the array and satisfy the condition that the values are smaller, larger, and later. First, I wrote the following code to test whether leetcode has s

)); Memset (C, 0, sizeof (INT) * (n + 1 )); TBL [0] = 1; C [0] = 1; For (INT I = 1; I { TBL [I] = 1; For (Int J = 0; j { If (TBL [J] =-1) continue; If (ARR [J]> arr [I] TBL [I] { TBL [I] = TBL [J] + 1; } } For (Int J = 0; j { If (ARR [J]> arr [I] TBL [I] = TBL [J] + 1) { C [I] + = C [J]; } } If (C [I] = 0) C [I] = 1; // when increasing /* You do not need the following code. For (Int J = 0; j { If (ARR [I] = arr [J] TBL [I] = TBL [J] C [I] = C [J]) { TBL [I] =

Poj 1952 buy low, buy lower maximum descent sub-sequence count, pojlower Question: Calculate the maximum length and number of sub-sequences for n. Analysis: Dp to avoid repeated Counting during counting. Code: // Poj 1952 // sep9 # include

This question has two questions, the first question is the longest descending subsequence.For the second ask the number of the longest descending sequence can be solved by asking the first question process. Set Maxcnt[i] to be the number of the longest descending sequence at the end of item I.For all J (1≤j≤i-1) if there is (S[j]>s[i] and maxlength[j]+1>maxlength[i]) then maxcnt[i]=maxcnt[j], otherwise if (maxlength[j]+1= = Maxlength[i]) can take advantage of the addition principle, maxcnt[i]=ma

The minimum spanning tree algorithm is simpleJust adding something new, there is some deeper understanding of the need for minimal spanning tree algorithms and the series of checks used.Some complex problems of the method#include Given the need to enumerate the sub-algorithms using several options.The workaround in the above. It uses a subset of the help of the binary counting method. A subset of the enumeration algorithm applies only to a relatively small set of elements.Taking the structure ab

CODE:#include Copyright NOTICE: This article for Bo Master original article, without Bo Master permission not reproduced.PAT 1092. To buy or don't to buy (STL)

;MP; for(inti=n;i>=1; i--){ if(Mp[a[i]]) next[i]=Mp[a[i]]; Elsenext[i]=-1; Mp[a[i]]=i; } REP (I,1, N) {Dp[i]=1; REP (J,1, I-1){ if(a[j]>A[i]) {Dp[i]=max (dp[i],dp[j]+1); }}} REP (I,1, N) cnt[i].init (); REP (i,1, N) { if(dp[i]==1) {Cnt[i].eq (1); Continue; } REP (J,1, I-1){ if(a[j]>A[i]) { if(dp[j]+1==Dp[i]) { if(next[j]!=-1next[j]Continue; Cnt[i]=Add (Cnt[i],cnt[j]); } } }

First we have to select the ticket window and the vending machine with the Payment Guide logo attached. When you have confirmed that the ticket information is correct, The conductor will be on the confirmation Output a two-dimensional code pattern It's like this. Then open Alipay Mobile Client Use the sweep feature Scan two-dimensional code for payment The little Buddy will ask. How to pay for the vending machine? On the vending machine there will be a Options for choosing how t

Say you have an array for whichITh element is the price of a given stock on dayI. If you were only permitted to complete at most one transaction (ie, buy one and every one share of the stock), design an algorithm to find the maximum profit. Idea: traverse the input array in sequence to record the current minimum value. The maximum value of the difference between each element and the current minimum value is required. 1 class solution {2 public: 3 i

Micro Letter buy Lottery ticket 1, in the mobile phone we open the micro-letter and then click Three points, and then click on "My bank card" as shown in the following figure. 2. Select Lottery Then enter into the bank card there will be a "lottery" click on it to be able to enter, if you do not add a bank card is will tell you to add Oh. 3, start to select a good All right, pick the number. This is easy. We just have to press the above condi

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With the advent of summer vacation, will be entering the University of graduates, we are ready to buy a favorite books, of course, the purchase of notebook is a headache, small part is from this age. So today I would like to share my 2015 summer notebook purchase experience, teach you how to choose the right notebook computer. If you have been to the science and technology hypermarkets, I feel once into the supermarket, the head is completely bl

Myth 1: Unrestricted is the best JS (profiteers): "This site to sell 100M support ASP space, without any restrictions, you can put forums, lakes, chat rooms and so on!" ”In fact, this is just a way to mislead users, so far, no server in the world to dare to say that their server support unlimited number of online! A Server main * Three major resources: bandwidth, memory and CPU, we judge the quality of the server from these three aspects, but these three resources are limited. If the server is l

There is an interesting question today:A group of friends wrote with a shell:#!/bin/bash# hundred million chicken, each chicken at least buy one all= -# Cocks per how many yuan read-P'Rooster How many text one:'gongji# hen per how many yuan read-P'How many hens a hen:'muji# can buy a few chickens per dollar read-P'chick How many only one article:'xiaoji# hundred dollars to

the mode of speaking, it is vulgar can no longer vulgar, is e-commerce. To be more vulgar, it is to do business and sell things. More simply, Groupon does retail, an industry that has been born in the era when people on Earth started using shells as money. The retail industry should be red on the earth can not be red Red Sea, big to the international chain of business giants, small to the community door of the smoke booth shop, fierce competition, meager profits. It is on the internet, from eb

Buy snacks Time limit:5000MS Memory Limit:262144KB 64bit IO Format:%lld %llu Submit Sta Tus Practice Hihocoder 1272 Description Little Ho likes to buy snacks at the grocery store during recess. Unfortunately, this semester he was in a teaching class, and a teacher's canteen sister is famous for Frosty. The first time to a teaching kiosk to buy snacks, small ho be

September School season has arrived, DIY computer as a student of the most cost-effective choice, the beginning of the school year will be driven by a small round of installed boom. Because the students themselves do not have a financial source, to buy a computer also need to spend their parents ' money, so many sensible children's shoes in DIY installed on the special focus on cost-effective, helpless store profiteers many, each year DIY installed by

This article is in the study summary, welcome reprint but please indicate the origin: http://blog.csdn.net/pistolove/article/details/43155725 Say you have an array for which the ith element are the price of a given the Design a algorithm to find the maximum profit. You may complete as many transactions as (ie, buy one and sell one share of the stock multiple times). However, you could not engage in multiple transactions at the same time (ie, your m

2007 5.18 days later, some webmaster will be surprised to find: part of the movie Network, music network, novel network, video information network, surprisingly cheap to start sales. Probably some stationmaster still did not know the new Information network dissemination right protection regulation is about to enter into effect in 2007 7.1 soon. is a website packing only 50 yuan, also do not buy. Saying no money to you, will also bring you trouble. So