* 1014. Sherlock Holmes's appointment

1/* 2 * Main. C 3*1014. sherlock Holmes appointment 4 * created on: September 1, 2014 5 * Author: in the boomkeeper 6 ***** section, ********** 7 */8 9 # include <stdio. h> 10 # include <string. h> 11 12/* 13 * Find "day" and "hh" 14 */15 void find_day_hour (const char str1 [] in "day hh: mm", const char str2 []) {16 17 int len1 = strlen (str1); 18 int len2 = strlen (str2); 19 int I; 20 char tempday, temphour; // store day and hh21 char hour [24] = {'0', '1', '2', '3', '4', '5 ',' 6', '7', '8', '9', 22 'A', 'B', 'C', 'D', 'E', 'F ', 'G', 'h', 'I', 'J', 'k', 'l', 'M', 'n '}; 23 24 // find day25 for (I = 0; I <(len1 <len2? Len1: len2); I ++) {26 if (str1 [I] = str2 [I]) & (str1 [I] <= 'G' & str1 [I]> = 'A') {27 tempday = str2 [I]; 28 break; 29} 30} 31 32 // calculate the day and print the 33 switch (tempday) {34 case 'A': printf ("mon"); break; 35 case 'B ': printf ("Tue"); break; 36 case 'C': printf ("wed"); break; 37 Case 'D': printf ("Thu"); break; 38 case 'E': printf ("fri"); break; 39 case 'F': printf ("sat"); break; 40 case 'G ': printf ("Sun" ); Break; 41} 42 43 // locate hh44 for (I + = 1; I <(len1 <len2? Len1: len2); I ++) {45 if (str1 [I] = str2 [I]) & (str1 [I]> = '0' & str1 [I] <= '9 ') | (str1 [I]> = 'A' & str1 [I] <= 'n') {46 temphour = str2 [I]; 47 break; 48} 49} 50 51 // calculate hh52 for (I = 0; I <24; I ++) {53 If (hour [I] = temphour) {54 // print hour 55 printf ("% 02i:", I); 56 break; 57} 58} 59} 60 61/* 62 * Find "day hh: "mm" 63 */64 void find_min (const char str3 [], const char str4 []) {65 66 int len3 = strlen (str3); 67 int Len4 = strlen (str4); 68 int I; 69 70 for (I = 0; I <(len3 <len4? Len3: len4); I ++) {71 If (str3 [I] <= 'Z' & str3 [I]> = 'A ') & (str4 [I] <= 'Z' & str4 [I]> = 'A') 72 If (str3 [I] = str4 [I]) 73 break; 74} 75 76 // print min 77 printf ("% 02i \ n", I); 78} 79 80 int main (void) {81 82 char str1 [60], str2 [60], str3 [60], str4 [60]; 83 84 gets (str1); 85 gets (str2 ); 86 gets (str3); 87 gets (str4); 88 89 find_day_hour (str1, str2); 90 find_min (str3, str4); 91 92 return 0; 93}

 

I had a hard time thinking about this question for a day. I still had to be patient. A pair of <= logical operators and curly braces almost drove me crazy!

 

Question link:

Http://pat.zju.edu.cn/contests/pat-b-practise/1014

 

 

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* 1014. Sherlock Holmes's appointment