178.LeetCode Rank Scores

Write a SQL query to rank scores. If there is a tie between the scores, both should has the same ranking. Note that after a tie, the next ranking number should is the next consecutive integer value. In the other words, there should is no "holes" between ranks.

+----+-------+| Id | Score |+----+-------+| 1  | 3.50  | | 2  | 3.65  | | 3  | 4.00  | | 4  | 3.85  | | 5  | 4.00  | | 6  | 3.65  |+ ----+-------+

For example, given the above Scores table, your query should generate the following report (order by highest score):

+-------+------+| Score | Rank |+-------+------+| 4.00  | 1    | | 4.00 |  1    | | 3.85  | 2    | | 3.65  | 3    | | 3.65  | 3    | | 3.50  | 4    |+-------+------+
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Idea: First find out score ranking in inner join scores table.

Selects1.score,s2.rankfromscores S1, (Selects.score, (SelectCount (1) from (SELECT distinctscorefromscores) Twheret.score >= S.score) rankfrom (SELECT distinctscorefromscores) s) s2wheres1.score = S2.scoreorder BYrank ASC

　　

178.LeetCode Rank Scores