A three-mesh operator problem

Don't know the result why is "excessive"? Ask the friend to know the answer under

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Don't know the result why is "excessive"? Ask the friend to know the answer under

By modifying the values, combining the results to analyze it.

Can see that $ A is true when executed ($a = = 5)? 1:0 for false $b = = 10
This result is true when returning excessive, for false return: (

For the convenience of reading best in ($a = = 5)? 1:0 Plus parentheses

I can only say JS ran out isyay

Does PHP do this?

($a ? ($a == 5 ? "yay" : "nay") : $b == 10) ? "excessive" : ":(";

If you're writing your own code, it might be easier to add parentheses, as the following should be a JavaScript-like result.

echo $a    ? ($a == 5 ? "yay" : "nay")     : ($b == 10 ? "excessive" : ":(");

If I'm right, I'm going to look straight in the back and divide the statement.

By partitioning can be simplified into
echo ' Yay '? ' Excessive ': ':(';

这样结果就会变掉

$a == 5 是真 返回yay

($a) ? ($a == 5) ? 'yay' : 'nay' : ($b == 10) ? 'excessive' : ':('; 这种写法你是从左往右读的，但机器不这么读，它可能是这样读的 ($a) ? (($a == 5) ? 'yay' : 'nay' : ($b == 10) ? 'excessive') : ':('; 电脑头都晕了

$a ? ($a == 5 ? 'yay' : 'nay') : ($b == 10 ? 'excessive' : ':('); 以后这样写，好吗

在语言设计上，js重输出，而php重计算。
类似的差别还有&&符和||符的计算结果、null变成字符串后的结果等。

