Also Talk About array A and &

Today I made a question:

 

1 # Include < Stdio. h >
2 Int Main ()
3 {
4 Int A [ 5 ] = { 1 , 2 , 3 , 4 , 5 };
5 Int   * PTR = ( Int * )( & A + 1 );
6 Printf ( " % D " , * ( + 1 ), * (PTR - 1 ));
7 }

 

You can try to see if the answer is the same as you think.

The key to this question is to understand the difference between A and.

A is a constant pointer to the int type.

& A is a pointer to int [5. Equivalent to int (* P) [5] = &;

Int * P = &;

At this time, the VC compiler will prompt a warning: 'int * 'differs in levels of indirection from 'int (*) [5]', that is, the type does not match

After obtaining a non-existent address (& A + 1), The type is forcibly converted to (int *), so * (p-1) points to the last element of.

Please correct us if anything is wrong!

 

 

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