Android calls Web Service

Make a web service with whatever you want. Assume that the obtained web service address is as follows:

Http: // 192.168.0.100/Android/webservice1.asmx

In this web service, a sum function is provided, and its implementation is as follows:

Publicint sum (int A, int B ){

Return A + B;

}

In Android, you can call

Publicvoid callws () throws parserconfigurationexception {

Final string server_url = "http: // 192.168.0.100/Android/webservice1.asmx/sum ";

Httppost request = new httppost (server_url );

List Params = new arraylist ();

Params. Add (New basicnamevaluepair ("A", "1 "));

Params. Add (New basicnamevaluepair ("B", "2 "));

Try {

Request. setentity (New urlencodedformentity (Params, HTTP. utf_8 ));

Httpresponse = new defaulthttpclient(.exe cute (request );

String result = "";

If (httpresponse. getstatusline (). getstatuscode ()! = 404 ){

Result = entityutils. tostring (httpresponse. getentity ());

}

New alertdialog. Builder (this). settitle ("hint"). setmessage (result)

. Setpositivebutton ("OK", null). Show ();

} Catch (exception e ){

New alertdialog. Builder (this). settitle ("hint"). setmessage (

E. getmessage (). setpositivebutton ("OK", null). Show ();

}

}

The above method can correctly obtain the Web service return value, but it is a complete XML and needs to be further parsed to get the desired result.

The resolution method is as follows:

Documentbuilderfactory factory = documentbuilderfactory. newinstance ();

Documentbuilder builder = factory. newdocumentbuilder ();

Inputstream is = new bytearrayinputstream (result. getbytes ("UTF-8 "));

Document dom = builder. parse (is );

String res = Dom. getdocumentelement (). getchildnodes (). Item (0). getnodevalue ();