Annular two-dimensional array (improved version)

Source: Internet
Author: User

There is still a problem with the last circular two-dimensional array, when it was not judged whether the resulting sub-matrices exceeded the range of the matrix, so the result would be problematic.

This is judged in the improved version of the program.

This problem is divided into two types, one is the maximum number of sub-rings, one is the largest sub-array is not ring. The part that is not in the loop has been implemented before, and the following is the ring part.

The idea is to expand the matrix to resemble a one-dimensional array, but the extent of the sub-matrix may go beyond the matrix if it expands. So there's a judgment here.

The improved program

#include <iostream>#include<time.h>using namespacestd;#defineMax (a) (a) > (b)? ( A):(B))#defineMAXN 100intA[MAXN][MAXN];intPARTSUM[MAXN][MAXN];//computes the and of the sub-matricesintMatrixsum (intSintTintIintj) {    returnPARTSUM[I][J]-partsum[i][t-1]-Partsum[s-1][J] + partsum[s-1][t-1];}intMain () {srand (unsigned) time (NULL)); intRow, col, I, J; cout<<"Please enter the number of rows and columns of the two-dimensional array:"; CIN>> Row >>Col;  for(i =1; I <= row; i++)    {         for(j =1; J <=2* Col-1; J + +)        {             for(j =1; J <=col; J + +) {A[i][j]= rand ()% --Ten; cout<< A[i][j] <<"\ t"; }             for(j = col+1; J <=2* Col-1; J + +) {A[i][j]= A[i][j-Col]; cout<< A[i][j] <<"\ t"; }            //cout << a[i][j] << "";} cout<<Endl; }         for(i =0; I <= row; i++) partsum[i][0] =0;  for(j =0; J <=2* col-1; J + +) partsum[0][J] =0; //calculate the part of the Matrix and     for(i =1; I <= row; i++)     for(j =1; J <= Col; J + +) Partsum[i][j]= A[i][j] + partsum[i-1][J] + partsum[i][j-1]-Partsum[i-1][j-1]; intN1, N2; intMaxsofar = a[1][1];  for(N1 =1; N1 <= Row; n1++)     for(N2 = n1; N2 <= Row; n2++)    {        //Set the sub-matrix upper and lower bounds to line N1 and line N2, take the maximum value in these sub-matrices, similar to the one-dimensional array to find the maximum value//not formed ring        intMaxendinghere = Matrixsum (N1,1, N2,1);  for(j =2; J <= col-1; J + +) {Maxendinghere= Max (Matrixsum (N1, J, N2, J), Matrixsum (N1, J, N2, J) +maxendinghere); Maxsofar=Max (Maxendinghere, Maxsofar); }        //Looping        intsum = matrixsum (n1,1, N2,1); intStart =sum; intsind =1;  for(i =2; I <=row; i++) {sum+=Matrixsum (N1, I, N2, i); if(Sum >start) {Start=sum; Sind=i; }} maxendinghere=Matrixsum (N1, J, N2, J); intTind =Row;  for(j = row-1; J >=1; j--) {sum+=Matrixsum (N1, J, N2, J); if(Sum >maxendinghere) {Maxendinghere=sum; Tind=J; }        }        if(sind<tind && start + maxendinghere>Maxsofar) {Maxsofar= Start +Maxendinghere; }} cout<<Maxsofar;}

Annular two-dimensional array (improved version)

Contact Us

The content source of this page is from Internet, which doesn't represent Alibaba Cloud's opinion; products and services mentioned on that page don't have any relationship with Alibaba Cloud. If the content of the page makes you feel confusing, please write us an email, we will handle the problem within 5 days after receiving your email.

If you find any instances of plagiarism from the community, please send an email to: info-contact@alibabacloud.com and provide relevant evidence. A staff member will contact you within 5 working days.

A Free Trial That Lets You Build Big!

Start building with 50+ products and up to 12 months usage for Elastic Compute Service

  • Sales Support

    1 on 1 presale consultation

  • After-Sales Support

    24/7 Technical Support 6 Free Tickets per Quarter Faster Response

  • Alibaba Cloud offers highly flexible support services tailored to meet your exact needs.