Application of dynamic type and anonymous type in ASP. Webapi

1. Dynamic type for WEBAPI calls

Suppose you need to call a WEBAPI,WEBAPI to return a JSON string. The string is as follows:

{"ProductId": "AN002501", "ProductName": "xx detergent", "Description": "", "UnitPrice": 9.9}

Q: How do I get the values in a JSON string?

The general practice is to build a class before deserializing it with JsonConvert. Examples are as follows:

(1) Building classes

1  Public classProduct2 {3 4          Public stringProductId {Get;Set; }5 6          Public stringProductName {Get;Set; }7 8          Public stringDescription {Get;Set; }9 Ten          Public decimalUnitPrice {Get;Set; } One  A}

(2) Deserialization:

1 string " {\ "productid\": \ "an002501\", \ "productname\": \ "xx washing powder \", \ "description\": \ "\", \ "unitprice\": 9.9} " ; 2 3 Dynamic Product = jsonconvert.deserializeobject<product> (jsonstring);

If you use a dynamic type , you do not need to construct a class to host the serialization. Examples are as follows:

1 Dynamic obj = jsonconvert.deserializeobject<dynamic> (jsonstring);

2. Anonymous type for WEBAPI output

Suppose you need to output the following JSON string: {"Id": "AN002501", "Price": 9.9}. Q: How do I achieve my goal?

The general practice is to first build a class that has the ID and price property, and then serialize it and then output it. Examples are as follows:

(1) Building classes

1  Public class simpleproduct 2 {3          Public string Get Set ; } 4 5          Public decimal Get Set ; } 6 }

(2) Output after serialization

 Public ActionResult Test1 () {    return Json (new"1333"9.9M  }, Jsonrequestbehavior.allowget);   
}

If you use anonymous types , you do not need to construct a class to host serialization. Examples are as follows:

 Public ActionResult Test2 () {    return Json (new"1333"9.9M  }, Jsonrequestbehavior.allowget);}

Application of dynamic type and anonymous type in ASP. Webapi