Arrays. copyof

Source: Internet
Author: User
 public static int[] copyOf(int[] original, int newLength) {        int[] copy = new int[newLength];        System.arraycopy(original, 0, copy, 0,                         Math.min(original.length, newLength));        return copy;    }

First, a new array is added, and then the new array is copied to return.

int[] strArray = new int[] {1,2,3,4};int[] copyArray=Arrays.copyOf(strArray,2);

The result copyarray is 1, 2.

int[] strArray = new int[] {1,2,3,4};int[] copyArray=Arrays.copyOf(strArray,10);

Result 1 2 3 4 0 0 0 0 0

No error is reported because the final array always follows the new array specified by newlength.

 

 

Use System. arraycopy:

int[] strArray = new int[] {1,2,3,4};        int[] copyArray = new int[4];        System.arraycopy(strArray, 0, copyArray, 0, 5);

Error: Java. Lang. arrayindexoutofboundsexception

If you change the last 5 to 3

copyArray :1 2 3 0 

 

Arrays. copyof

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