BAPC2014 J&&hunnu11590:jury Jeopardy

Source: Internet
Author: User

Test instructions

A maze, people start in the exit position, asked to traverse a maze, back to the initial position, now give a plan to walk, to draw out the maze

People start facing to the right

F: Take a step forward

R: Turn right and take a step forward

L: Turn left and take a step forward

B: Turn back and take a step forward


Ideas:

Direct simulation can


#include <iostream> #include <stdio.h> #include <string.h> #include <stack> #include <queue > #include <map> #include <set> #include <vector> #include <math.h> #include <bitset># Include <algorithm> #include <climits>using namespace std; #define LS 2*i#define rs 2*i+1#define up (i,x,y) for (i=x;i<=y;i++) #define DOWN (i,x,y) for (i=x;i>=y;i--) #define MEM (a,x) memset (A,x,sizeof (a)) #define W (a) while (a)  #define GCD (A, B) __gcd (A, b) #define LL long long#define ULL unsigned long long#define N 100005#define INF 0x3f3f3f3f#define EXP 1e-8#define rank rank1const int mod = 1000000007;int T,len;char str[1000000];int to[4][2]={0,1,1,0,0,-1,-1,0},vis[30    0][300];int Main () {int i,j,k;    scanf ("%d", &t);    printf ("%d\n", t);        while (t--) {MEM (vis,0);        scanf ("%s", str);        len = strlen (str);        int r = 0;        int x = 128,y=128;        Vis[x][y] = 1;        int maxx,maxy,minx,miny; Maxx = Maxy = Minx = MIny = 128;                for (i = 0;i<len;i++) {if (str[i]== ' F ') {x+=to[r][0];                Y+=TO[R][1];            Vis[x][y] = 1;                } else if (str[i]== ' R ') {r = (r+1)%4;                X+=TO[R][0];                Y+=TO[R][1];            Vis[x][y] = 1;                } else if (str[i]== ' B ') {r = (r+2)%4;                X+=TO[R][0];                Y+=TO[R][1];            Vis[x][y] = 1;                } else if (str[i]== ' L ') {r = (r+3)%4;                X+=TO[R][0];                Y+=TO[R][1];            Vis[x][y] = 1;            } Maxx = max (maxx,x);            Maxy = max (maxy,y);            Minx = min (minx,x);        miny = min (miny,y);        } printf ("%d%d\n", maxx-minx+3,maxy-miny+2);        for (i = minx-1;i<=maxx+1;i++) {for (j = miny;j<=maxy+1;j++) {        if (Vis[i][j]) printf (".");            else printf ("#");        } printf ("\ n"); }} return 0;}


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BAPC2014 J&&hunnu11590:jury Jeopardy

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