C language-Enter a string to convert consecutive numeric characters to numbers

Enter a string with numeric and non-numeric characters, for example:

A123CDF 456.78cpc876.9er 849.1

The successive numbers are used as a real number, which is stored in an array a . For example 123 stored in a[0],456.78 stored in a[2], and so on, Statistics total number of the number, and output these numbers.

#include <stdio.h>

#include <string.h>

#include <math.h>

#define N 50

int number (char str[],float num[]);

int main () {

Char Str[n];

float Num[n];

int k,i;

Gets (str);

K=number (Str,num);

printf ("%d number \ n", k);

for (i=0; i<k; i++)

{

if (num[i]-(int) num[i]==0)

printf ("%.0f", Num[i]);

else printf ("%g", Num[i]);

}

return 0;

}

int number (char str[],float num[]) {

int i,j;

int k=0;

int t;

float sum=0;

while (str[i]! = ' + ')

{

if (str[i]>= ' 0 ' && str[i]<= ' 9 ') {

sum=0;

while (str[i]>= ' 0 ' && str[i]<= ' 9 ')

{

sum=sum*10+str[i]-' 0 ';

i++;

if (str[i]== '. ')

{

t=i;

i++;

while (str[i]>= ' 0 ' && str[i]<= ' 9 ')

{

sum=sum+ (str[i]-' 0 ') *pow (10,t-i);

i++;

}

}

}

Num[k]=sum;

k++;

}

if (str[i]== '. ')

{

sum=0;

t=i;

i++;

while (str[i]>= ' 0 ' && str[i]<= ' 9 ')

{

sum=sum+ (str[i]-' 0 ') *pow (10,t-i);

i++;

}

Num[k]=sum;

k++;

}

i++;

}

return k;

}

C language-Enter a string to convert consecutive numeric characters to numbers