C Language Example series-------fourth day

7. The output shape is right triangle 99 multiplication table. The shape is as follows://*   1   2   3   4   5    6   7   8   9//1   1    2   2   4//3   3   6   9//4    4   8   12  16//5   5   10   15  20  25//6   6   12  18   24  30  36//7   7   14  21  28   35  42  49//8   8   16  24  32   40  48  56  64 //9   9   18   27  36  45  54  63  72  81//This is the code I wrote myself, and here's the book.The code #include<stdio.h>int main () {int i,j;printf ("*  ");//The asterisk for (i=1;i<=9;i++) that starts with a separate output printf ("%d  ", I);//With A for () loop, output a row from 1 to 9, which is the first row of printf ("\ n") of the multiplication table; for (i=1;i<=9;i++)     //needs {                .    //himself printf ("%d  ", I);    //comprehend for (j=1;j<=i;j++)    / /。。。 printf ("%d  ", I*j),  //,,,printf ("\ n");      //}return 0;} This is the code written in the book/* #include <stdio.h>int main (void) {int i,j,k;printf ("*"); for (i=1;i<10;i++) printf (" %4d ", i);//The first row of printf (" \ n ") is first output with a for () loop, and for (j=1;j<10;j++)   //requires {                   //himself printf ("%2d", j);    //comprehend for (k=1;k<=j;k++)   //... printf ("%4d", j*k);  //... printf ("\ n");} return 0;} */

8, increasing herd: If a heifer, starting from the 4th year, the annual birth of a cow, according to the law,//The number of cows in the first n years? /* #include <stdio.h>int main () {int i,year,oxnum,oxnum1,oxnum2,oxnum3;printf ("Enter Year:"); scanf ("%d",& year), for (i=1;i<=year;i++) {if (i<4) Oxnum=oxnum1=oxnum2=oxnum3=1;else{oxnum=oxnum1+oxnum3;oxnum3=oxnum2;o Xnum2=oxnum1;oxnum1=oxnum;} printf ("I=%2d ox number=%3d\n", i,oxnum);} return 0;} */

This article from "Peng Brother's Blog" blog, declined reproduced!

C Language Example series-------fourth day