c+ pointer arithmetic

Main () {

     charstr1[]={' A ', ' B ', ' C ', ' d '};     charstr2 = {' 1 ', ' e '},{' Q ', ' d '},{' g ', ' H '} };     CHAR*P_STR1 = "123456";    printf ("%c \ r \ n", str1);    printf ("%c \ r\n ", * (str1+1));    printf ("%c \ r \ n ", * (* (str2+1) +1));    printf ("%s \ r \ n ", p_str1+1);     printf ("%c \ r \ n", * (p_str1+1));    printf ("%c \ r \ n", p_str1);      return0; }  Results:b b d 2345622   How to understand str1[]   and *? [] and * Both have two meanings and functions, which are embodied in the definition and operation. [] At the time of definition, the current definition is an array, * at the time of definition, a pointer is currently defined. The str1 in str1[] represents the pointer to the first element of the array, and we don't have to look at the pointer so mysteriously. He has nothing to do with a general variable except that he has an address integer in it, and the pointer can be run in a special way.   If a pointer is P then p is just his representation. The memory location in the symbol table is 54321111, and the location of the memory has another address, *p is the value of the memory that the pointer points to. P+1, what's going on? If the value of P is 54321111, then p+1=54321112? No, the addition operation of the pointer is not a simple arithmetic operation. First, the pointer depends on the type of variable it points to, and if the type is x in memory placeholder 8, then p+1 should be p+8*1. We look at  char str2 ={{' 1 ', ' e '},{' Q ', ' d '},{' g ', ' H '}; First str2 is the pointer to the first element of the entire array, and str2+1 gets the pointer to the second array, * (str2+1) Gets the pointer inside theContent, what is in this, because this is a two-dimensional array so, the contents of this is a pointer, * (* (str2+1) +1) so that the D is taken.  str1  what does it actually do? At the time of definition, he was explaining that STR1 was a pointer to a two-element, and it actually completed the calculation (str1+2) when the operation was performed (of course, when we referred to the value operation). That is to say, the   pointer  = * (pointer +x)   These two are exactly equal operations.

c+ pointer Operation