Cc150-array and String 1.3

Source: Internet
Author: User

Problem:

Given, write a method to decide if one are a permutation of the other

Solution:

1. Sort strings and return weather str1 equal to STR2

2. Record number of char of str1 and detract str2 weather equal to zero for every items.

Code

public static Boolean changable (String str1, String str2) {
if (Str1.length ()!=str2.length ()) return false;
int[] index = new int[256];
for (int i =0; i<str1.length (); i++) {
int val = Str1.charat (i);
index[val]++;
}
for (int i=0; i<str2.length (); i++) {
int val = Str2.charat (i);
index[val]--;
}
for (int i = 0; i < index.length; i++) {
if (index[i]!=0)
return false;
}
return true;
}

Cc150-array and String 1.3

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