Code for pagination based on jqGrid in JQuery

Source: Internet
Author: User
The code is as follows: Copy code
<! DOCTYPE html PUBLIC "-// W3C // dtd html 4.01 Transitional // EN" "http://www.w3.org/TR/html4/loose.dtd">
<Html>
<Head>
<Meta http-equiv = "Content-Type" content = "text/html; charset = UTF-8">
<Title> Insert title here </title>
<Link rel = "stylesheet" type = "text/css" media = "screen"
Href = "js/themes/basic/grid.css"/>
<Script type = "text/javascript" src = "js/jquery. js"> </script>
<Script type = "text/javascript" src = "js/jquery. jqGrid. js"> </script>
<Script type = "text/javascript">
JQuery (document). ready (function (){
JQuery ("# myTab"). jqGrid ({// myTab: The table id mounted to the data
Datatype: "json", // use JSON data here
Url: 'dataservlet', // This is the data request address.
Height: 250,
Width: 400,
ColNames: ['Number', 'name', 'phone'],
ColModel :[
{Name: 'id', index: 'id', width: 60, sorttype: "int "},
{Name: 'name', index: 'name', width: 90 },
{Name: 'phone', index: 'phone', width: 100}
],
Pager: 'pager', // pager toolbar, pager: the id of the paging DIV
Imgpath: 'JS/themes/basic/images ', // path for storing images
RowNum: 10, // number of records per page
Viewrecords: true, // whether to display the number of rows
RowList: [, 30], // you can adjust the number of records displayed on each page
Multiselect: false, // whether multiple selections are supported
Caption: "Information Display"
});
});
</Script>
</Head>
<Body>
<Table id = "myTab" class = "scroll" cellpadding = "0" cellspacing = "0"> </table>
<Div id = "pager" class = "scroll"> </div>
</Body>
</Html>


The data in the backend servlet is simulated.

Java code
  

The code is as follows: Copy code
Public class DataServlet extends HttpServlet {
Private static final long serialVersionUID = 1L;
  
      
Protected void doGet (HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
    }   
  
      
Protected void doPost (HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
String page = request. getParameter ("page"); // Obtain the current page number. Note that this is a parameter of jqgrid.
String rows = request. getParameter ("rows"); // Obtain the number of lines displayed on each page. Note that this is the jqgrid parameter.
Int totalRecord = 80; // The total number of records (it should be obtained according to the database. Here it is only a simulation)
Int totalPage = totalRecord % Integer. parseInt (rows) = 0? TotalRecord
/Integer. parseInt (rows): totalRecord/Integer. parseInt (rows)
+ 1; // calculate the total number of pages
Try {
Int index = (Integer. parseInt (page)-1) * Integer. parseInt (rows); // number of start Records
Int pageSize = Integer. parseInt (rows );
// Simulate JSON data object construction
String json = "{total:" + totalPage + ", page:" + page
+ ", Records:" + totalRecord + ", rows :[";
For (int I = index; I <pageSize + index & I <totalRecord; I ++ ){
Json + = "{cell: ['id" + I + "', 'name" + I + "', 'phone" + I
+ "']}";
If (I! = PageSize + index-1 & I! = TotalRecord-1 ){
Json + = ",";
                }   
            }   
Json + = "]}";
Response. getWriter (). write (json); // return JSON data to the page
} Catch (Exception ex ){
        }   
    }   
}  

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