English problem face:
De Prezer loves movies and series. He had watched theTroy for like the Times and also he was a big fan of theSupernatural series. So, he does some researches and found a cursed object which hadn lights on it and initially all of them were Turne D off. Because of theTroy, he called that object Troy.
He looked and saw a note on the IT in khikulish (language of people of Khikuland): "Ma in Hame rah Umadim, h Ala Migi ...? ... Mage man De prezer am k mikhay mano ...? .... Man SE sale ... To Boro .... Beshur manam miram ... o mishuram ".
He doesn ' t know khikulish, so just ignored the note and tested theTroy.
he realized, the light number i stays Turned on for exactly a i seconds, and Then it turns itself off (if it was turned on, in Time t , in time t ? +? a i ?-? 1 It'll be turned on, but on Time t ? +? A i it won ' t is) and the next light would be turned on (If i ? <? n , next light number i ? +?1 , otherwise it's light with Number 1 ).
For example if n-=?2 and we turn on the first light in time0, it'll be is turned on hole inte Rval [0,? A1) and in hole interval [a1,? A1?+? A2) The second light is turned on and so on.
In time 0 He turns on the light number1.
De Prezer also loves query. So he gives you Q queries. In each query he'll give you an integer T (the time a revengeful ghost attacked him) and you should print the numb Er of the light which is turned on, in timet.
Input
The first line of input contains the integers n and Q.
The second line contains n space separated integers,a1,? A2,?...,? An .
The next Q lines, each line contains a single integert .
1?≤? n,? q. ≤?105
1?≤? a i? ≤?109
1?≤? t. ≤?10
Output
For each query, print the answer on one line.
That is, there are n lights, and then give each lamp on the time of the light (the first light from the moment 0 light up until the moment 0+a1-1, the second in the A1 moment, and so on), and then the question to ask the Q Group, ask the content is a T, you give the T moment when the light of the lamp. My practice is that every time I ask for a two-point search, the complexity of log2n 10^5 times to ask to accept.
Sample Test (s):
Input
5 71 2 3 4 51237141516
Output
2234512
This set of test data is still the industry conscience, burst out of the hole may be wrong, this string of lights is the cycle of the end-to-end light, so that T is 10^18 so large, to take the mold.
Code:
#include <iostream> #include <stdio.h>using namespace std;long long int start[100005];//Each lamp starts to light at a time long long int end[100005];//each lamp on the finish time int n,q,a;long long int t;int work (long long int ask)//binary lookup function {int p=1; int p1=1; int p2=n; while (ask<start[p]| | Ask>end[p]) {p= (P1+P2)/2; if (Ask>=start[p]&&ask<=end[p]) {break; }else if (Ask>=start[p1]&&ask<=end[p1]) {p=p1; Break }else if (Ask>=start[p2]&&ask<=end[p2]) {p=p2; Break }else if (Ask<start[p]&&ask>end[p1]) {p2=p; }else if (Ask>end[p]&&ask<start[p2]) {p1=p; }} return p;//p is the lamp}int main () {scanf ("%d%d", &n,&q); start[1]=0; for (int i=1;i<=n;i++) {scanf ("%d", &a); End[i]=start[i]+a-1; Start[i+1]=start[i]+a; } while (q--) { scanf ("%i64d", &t); printf ("%d\n", Work (t%start[n+1])); } return 0;}
Codeforces Hello2015 first question cursed Query