Title Description
Description
Fruit sister today in a good mood, came to the fruit street.
Fruit Street has n fruit shop, in a straight line structure, numbered 1~n, each store can buy fruit can also sell fruit, and the same shop to sell and buy the same price.
Learn Oi fruit sister quickly found a way to make money: in a fruit shop to buy a fruit, and then sell to another shop, make a difference.
In the fruit when the elder sister, Cgh suddenly appeared, he in order to embarrass Fruit elder sister, give M a question, each question request fruit elder sister from the X home to the first shop, on the way only choose a shop to buy a fruit, then choose a shop (can be the same shop, but can't go back) sell out, Ask for the maximum amount of money you can make in each question.
Enter a description
Input Description
The first line is n, which means n stores
Down n A positive integer that represents the price of an apple per store.
Down an integer m, which represents down there m inquiries.
Down there are M-lines, two integers x and y per line, indicating the departure from the X home to the nth store.
Output description
Output Description
There are M lines.
Each line corresponds to a query, an integer, indicating the face of cgh each query, fruit elder sister can earn up to how much money.
Sample input
Sample Input
10
2 8 15 1 10 5 19 19 3 5
4
6 6
2 8
2 2
6 3
Sample output
Sample Output
0
18
0
14
Data range and Tips
Data Size & Hint
0<= Apple Price <=10^8
0<n,m<=200000
/*consider the line segment tree, each answer may be obtained within the interval, can also be obtained between the interval, the first case directly in the revision of the time to record, the second can be used in DFS sequence*/#include<iostream>#include<cstdio>#include<string>#include<cstring>#include<algorithm>#include<cmath>#include<vector>#definell Long Long#defineFo (i,l,r) for (int i = l;i <= r;i++)#defineFD (I,L,R) for (int i = r;i >= l;i--)#defineLson l,m,rt<<1#defineRson m+1,r,rt<<1|1using namespacestd;Const intN =200000; ll read () {ll x=0, f=1; CharCh=GetChar (); while(! (ch>='0'&&ch<='9')){if(ch=='-') f=-1; ch=GetChar ();}; while(ch>='0'&&ch<='9') {x=x*Ten+ (ch-'0'); ch=GetChar ();}; returnx*F;}intn,m,u,v;BOOLf;ll minv[n<<4],maxv[n<<4],d1[n<<4],d2[n<<4],reca[n<<4],recb[n<<4],val[n],cnt;ll ans;voidMaintain (intRT) {Minv[rt]= Min (minv[rt<<1],minv[rt<<1|1]); MAXV[RT]= Max (maxv[rt<<1],maxv[rt<<1|1]); D1[RT]= Max (d1[rt<<1],d1[rt<<1|1]); D1[RT]= Max (d1[rt],maxv[rt<<1|1]-minv[rt<<1]); D2[RT]= Max (d2[rt<<1],d2[rt<<1|1]); D2[RT]= Max (d2[rt],maxv[rt<<1]-minv[rt<<1|1]);}voidBuildintLintRintRT) { if(L = =R) {Minv[rt]= Maxv[rt] =Val[l]; D1[RT]= D2[rt] =0; }Else{ intm = (L + r) >>1; Build (Lson); Build (Rson); Maintain (RT); } }voidQueryintLintRintRT) { if(U <= l && v >=R) { if(!f) ans =Max (Ans,d1[rt]); ElseAns =Max (Ans,d2[rt]); reca[++CNT] =Minv[rt]; RECB[CNT]=Maxv[rt]; }Else{ intm = (L + r) >>1; if(U <=m) query (Lson); if(V >m) query (Rson); }}voidsolve () {CNT= ans =0; F=false; if(U >v) {swap (U,V); F=true; } query (1N1); LL TMP=987654321012345LL; if(!f) {FO (i,2, CNT) {tmp= Min (tmp,reca[i-1]); Ans= Max (ans,recb[i]-tmp); } }Else{FD (i,1, cnt-1) {tmp= Min (tmp,reca[i+1]); Ans= Max (ans,recb[i]-tmp); }} printf ("%lld\n", ans);}intMain () {n=read (); Fo (i,1, n) val[i] =read (); Build (1N1); M=read (); Fo (i,1, M) {u= Read (); v=read (); solve (); } return 0;}
codevs3304 Fruit Street Shopping