Recommended Online Example: http://acm.nyist.net/JudgeOnline/problem.php?pid=16
Title Excerpt:
Rectangle Nesting time limit:MS | Memory limit:65535 KB Difficulty:4
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Describe
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there are n rectangles, each of which can be described by a A, a, long and wide. A rectangle x (A, b) can be nested in the rectangle y (c,d) when and only if A<c,b<d or b<c,a<d (equivalent to rotation X90 degrees). For example (1,5) can be nested within (6,2), but not nested in (3,4). Your task is to select as many rectangles as possible, so that each rectangle can be nested within the next rectangle, except for the last one.
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Input
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The
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first line is a positive positive N (0<N<10), which indicates the number of test data groups,
The first row of each set of test data is a positive positive n, indicating the number of rectangles in the group's test data (n<=1000)
The next n rows, each with two numbers, A, B (0<a,b<100), represent the length and width of the rectangle
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Output
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each set of test data outputs a number that represents the maximum number of rectangles that meet the criteria, one row for each set of outputs
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Sample input
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1101 22 45 86 107 93 15 812 109 72 2
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Sample output
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5
Print1 is the maximum number of rectangles to be output according to the topic
Print2 is to output the selected rectangle
#include"iostream"#include"Cstdio"#include"CString"#include"algorithm"using namespacestd;#defineMAXN 100intN,max;intDP[MAXN];structnode{intL,w;} MAT[MAXN];BOOLCMP (node A,node b) {if(A.L!=B.L)returna.l<B.L; returna.w<B.W;}intMaxintAintb) { returnA>b?a:b;}voidSwapint&a,int&b) { intT; T=A; A=b; b=t;}voidInit () {cin>>N; intTL,TW; for(intI=1; i<=n;i++) {scanf ("%d%d",&tl,&TW); if(tl<tw) Swap (TL,TW); MAT[I].L=tl;mat[i].w=tw; } memset (DP,0,sizeof(DP));}voidWork () {Sort (Mat+1, mat+1+n,cmp); Max=-1; for(intI=1; i<=n;i++) { for(intj=1; j<=i;j++) { if(mat[i].l>mat[j].l&&mat[i].w>MAT[J].W) {Dp[i]=max (dp[i],dp[j]+1); }} Dp[i]=max (Dp[i],1); Max=Max (max,dp[i]); }}voidPrint1 () {printf ("%d\n", Max (1, Max));}voidPrint2 (inti) {printf ("%d", i); for(intj=1; j<=n;j++)if(dp[i]==dp[j]+1&&MAT[I].L>MAT[J].L&&MAT[I].W>MAT[J].W) {Print2 (j); Break;}}intMain () {intT; CIN>>T; while(t--) {Init (); Work (); Print1 (); //Print2 (n);cout<<endl; } return 0;} 1
Dag model (Rectangle nesting)