In the direct insertion sort, in Min's book it is necessary to set the Sentinel, the role of the Sentinel is to avoid the array out of bounds, so in the first position to set Sentinel, after thinking this algorithm for me the most worthy of learning is to compare the location of the move at the same time, this will reduce the complexity of time
Data structure for
#define MAXSIZE 20int KeyType;struct sqList{ KeyType r[MAXSIZE+1]; int length;};
The code in the book containing the Sentinel is as follows
voidSinsertsort (SqList L,intLen) {//There is a very worthwhile place to learn, which is to move directly while comparing if(len<=1)return; for(intI=2; i<=len;i++) {if(l.r[i-1]>l.r[i]) {l.r[0]=l.r[i];intJ for(j=i-1; l.r[j]>l.r[0];--J)//This prevents the array from oversteppingl.r[j+1]=L.R[J]; l.r[j+1]=l.r[0]; } }cout<<"with Sentinel's direct insertion sort"<<endl; for(intI=1; i<=l.length;i++)cout<<L.r[i]<<" ";cout<<endl;}
The code in the book is the use of a space in the array itself l.r[0]. For people who have just written code, moving data while comparing data saves time
for (j=i-1; L.R[J]>L.R[0];–J)
L.R[J+1]=L.R[J];
In fact, it's the same with other spaces as Sentinels.
voidSInsertSort1 (SqList L,intLen) {//written by yourself without a sentinel if(len<=1)return; for(intI=1; i<len;++i) {if(l.r[i-1]>l.r[i]) {intJintTemp=l.r[i]; for(j=i-1; l.r[j]>temp&&j>=0;--j) l.r[j+1]=L.R[J]; l.r[j+1]=temp; } }cout<<endl;cout<<"No Sentinel's direct insertion sort"<<endl; for(intI=0; i<l.length;i++)cout<<L.r[i]<<" ";cout<<endl;}
The use of j>0 as a sentry in this code is actually the same as the principle in the book, and the reason for this is to make it clear that the Sentinel's meaning lies.
int main () {sqlist L;L. R[1]= the;L. R[2]= -;L. R[3]= $;L. R[4]= the;L. R[5]= the;L. R[6]= -;L. R[7]= -;L. R[8]= the;L. Length=8;SqList L1;L1. R[0]= the;L1. R[1]= -;L1. R[2]= $;L1. R[3]= the;L1. R[4]= the;L1. R[5]= -;L1. R[6]= -;L1. R[7]= the;L1. Length=8;Sinsertsort (L,8);SInsertSort1 (L1,8); /*binsertsort (l,8); BInsertSort1 (l1,8); * *Return0;}
Time complexity is O (N2) in direct insert sort
In fact, it is not very clear here, if the function void SIS1 (sqlist &l,int len) in the L with the accessor is not written j>=0 run the result is also correct, as if the compiler can automatically determine whether it is out of bounds, but L do not have to take the address, it must have a J >=0, otherwise the array will go out of bounds.
Direct insertion sort thinking and code implementation