Euler's plan 6th questions

The sum of the squares of the first ten natural numbers is,

12 + 22 +... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 +... + 10) 2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

 

Long sumofsquares = 0; For (INT I = 1; I <= 100; I ++) {sumofsquares + = (long) math. pow (I, 2) ;}long sum = 0; For (INT I = 1; I <= 100; I ++) {sum + = I ;} long squaresofsum = (long) math. pow (sum, 2); console. writeline ("{0}-{1} = {2}", squaresofsum, sumofsquares, squaresofsum-sumofsquares );