[Hackerrank] gem stones

Source: Internet
Author: User

Gem stones

John has discovered various rocks. each rock is composed of various elements, and each element is represented by a lowercase Latin letter from 'A' to 'Z '. an element can be present multiple times in a rock. an element is called a 'gem-element' if it occurs at least once in each of the rocks.

Given the list of rocks with their compositions, display the number of GEM-elements that exist in those rocks.

Input Format
The first line consistsN, The number of rocks.
Each of the nextNLines contain rocks' composition. Each composition consists of lowercase letters of English alphabet.

Output Format
Print the number gem-elements that exist in those rocks.

Constraints
1 ≤ n ≤100
Each composition consists of only small Latin letters ('A'-'Z ').
1 ≤ length of each composition ≤100

 

Question:

 1 import java.io.*; 2 import java.util.*; 3 import java.math.*; 4  5  6 public class Solution {    7    static int[] Gem_Stones(String[] ele){ 8        int[] answer = new int[27]; 9        for(int i = 0;i < ele.length;i++){10            boolean[] has = new boolean[27];11            for(int j =0;j < ele[i].length();j++){12                char temp = ele[i].charAt(j);13                if(!has[temp-‘a‘]){14                    answer[temp-‘a‘]++;15                    has[temp-‘a‘] = true;16                }17            }18        }19        return answer;20    }21 22 23  public static void main(String[] args) {24         Scanner in = new Scanner(System.in);25         int t;26         t = in.nextInt();27         String[] strings= new String[t];28         for(int i = 0;i < t;i++){29             strings[i] = in.next(); 30         }31         int[] answer = Gem_Stones(strings);32         int count = 0;33         for(int i = 0;i < answer.length;i++)34             if(answer[i]== t )35                 count++;36         System.out.print(count);37    }38 }

 

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