HDU 1003 Max sum

Max sumtime limit: 2000/1000 MS (Java/others) memory limit: 65536/32768 K (Java/others) total submission (s): 143429 accepted submission (s): 33431

Problem descriptiongiven a sequence a [1], a [2], a [3] ...... A [n], your job is to calculate the max sum of a sub-sequence. for example, given (6,-1, 5, 4,-7), the Max sum in this sequence is 6 + (-1) + 5 + 4 = 14.
 
Inputthe first line of the input contains an integer T (1 <= T <= 20) which means the number of test cases. then T lines follow, each line starts with a number N (1 <= n <= 100000), then n integers followed (all the integers are between-1000 and 1000 ).
 
Outputfor each test case, you should output two lines. the first line is "case #:", # means the number of the test case. the second line contains three integers, the max sum in the sequence, the start position of the sub-sequence, the end position of the sub-sequence. if there are more than one result, output the first one. output a blank line between two cases.
 
Sample Input

25 6 -1 5 4 -77 0 6 -1 1 -6 7 -5

 
Sample output

Case 1:14 1 4Case 2:7 1 6

 

#include<stdio.h>#include<string.h>#include<algorithm>#include<iostream>using namespace std;int main (){    int T,n,a[100105];    int i,j,sum,max,s,e,t;    cin>>T;    for(i=1;i<=T;i++)    {        cin>>n;        for(j=0;j<n;j++)           cin>>a[j];        sum=a[0];        max=a[0];        t=0;        s=0;        e=0;        for(j=1;j<n;j++)        {           if(sum<0)           {               sum=0;               t=j;           }           sum+=a[j];           if(sum>max)            {                max=sum;                e=j;                s=t;            }        }        cout<<"Case"<<" "<<i<<":"<<endl;        cout<<max<<" "<<s+1<<" "<<e+1<<endl;        if(i<T)            cout<<endl;    }         return 0;}