How to store database information in an array using php
Source: Internet
Author: User
How to store database information in the array with php $ conn = mysql_connect ('localhost', 'root', ''); & nbsp; $ selectdb = mysql_select_db (& quot; career & quot;, $ conn); // How does mysql_quer store database information in an array using php?
$ Conn = mysql_connect ('localhost', 'root ','');
$ Selectdb = mysql_select_db ("career", $ conn );
// Mysql_query ("set names 'gbk '");
$ Result = mysql_query ("SELECT acode FROM code ");
$ Row = mysql_fetch_array ($ result, MYSQL_NUM );
While ($ row)
{
For ($ I = 0; $ I <= count ($ row)-1; $ I ++)
{
Echo $ row [$ I];
}
}
I plan to store a column in the database into an array, but the output result only outputs the content of $ row [0], which does not exist at the end, it seems that the problem is that only one $ row [0] exists in mysql_fetch_array when I use print_R to output $ row. how can I fully store a column in the database into an array?
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