Huawei trial (4)

Intermediate question
Description
Enter 10 numbers in ascending order of digits and digits. If the numbers are the same, they are sorted in ascending order.
Input Description: 10 positive integers, which must be within the int range and separated by spaces.
Output Description: 10 numbers. The values are separated by spaces. The last number is not followed by spaces.
Input example: 11 3 2 4 5 9 8 7 10 6
Output example: 10 2 11 3 4 5 6 7 8 9
Solution: Call the sort function that comes with C ++ and rewrite the Compare function.

#include<string>#include<algorithm>#include<sstream>#include<iostream>#include<vector>using namespace std;bool cmp(string &s1,string &s2){   unsigned len1;   len1 = s1.size();   unsigned len2 ;   len2 = s2.size();   unsigned res1=0,res2=0;   for(unsigned i = 0;i<len1;i++)   {     res1 += (s1[i]-‘0‘);   }   for(unsigned j=0;j<len2;j++)   {     res2 +=(s2[j]-‘0‘);   }            if(res1==res2)   {          istringstream is1(s1),is2(s2);      unsigned d1,d2;      is1>>d1;      is2>>d2;         return (d1<d2);         }     return (res1<res2);  }void main(){       vector<string> ves(10,"");    for(int i=0;i<10;i++)        cin>>ves[i];    sort(ves.begin(),ves.end(),cmp);    for(int i=0;i<10;i++)    { 
       cout<<ves[i];
       if(i!=9)
         cout<<" ";
    }
    cout<<endl;   }