Is the array name a pointer?

Is the array name a pointer? If not, what kind of structure is the array name? Please explain.

I will describe the differences between array names and pointers that I know.

1. The address is the same and the size is different.
See the following code:
1 int arr [10];
2 int * p = arr;
3 cout <arr <endl;
4 cout <p <endl;
5 cout <sizeof (arr) <endl; // The result is 40
6 cout <sizeof (p) <endl; // The result is 4.
Arr is the array name, and p is the pointer.
The output values of rows 3rd and 4 are the same, that is, both arr and p are the first addresses of arrays. Rows 5th and 6 have different results. The size of arr is the size of the entire array, and the size of p is the size of the pointer.
Why is the size of arr 40?

2. You can use pointers as parameters.
Of course, the pointer parameter is a pointer. An array can be an array or a pointer. The following code demonstrates that the form parameter of an array can be a pointer.
1 void fun (int * p)
2 {
3 cout <p [0] <endl;
4}
5
6
7 int main ()
8 {
9 int arr [10] = {0 };
10 int * p = arr;
11 fun (arr );
12
13 return 0;
14}
This shows that the array name can be used as a pointer.

3. the pointer can be automatically added, but the array name cannot.

1 int arr [10] = {0 };
2 int * p = arr;
3 arr ++;
4 p ++;
When the array name is self-added, the program compilation will fail. From this point, we can see that the array name is a constant (const modifier ).

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4. The size of the array name as a parameter is the same as that of the pointer.

1 void fun (int arr [])
2 {
3 cout <sizeof (arr) <endl; // The result is 4.
4 arr ++; // compiled successfully
5}
6
The size of arr is changed to 4, and the arr ++ compilation is successful. The arr as a parameter has completely become a pointer.

The above is the difference between the pointer and the array name I know. If there are other differences, please leave a message to tell me. If anyone knows what structure the array name is, please leave a message to inform me, thank you.

From C Xiaojia