JavaScript contains an array of objects to remove weight

Array.prototype.clearRepeat =function(){  varresult =[], obj= {};  for(vari = 0; I < This. length; i++){     if(typeof( This[i] = = = = "Object"){        varobjname = "Object:";  for(varXinch  This[i]) {objname+=x; ObjName+= This[i][x]; }        if(!Obj[objname]) {Obj[objname]= "New"; Result.push ( This[i]); }    }    Else if(!obj[typeof( This[i]) + This[i]]) {Result.push ( This[i]); obj[typeof( This[i]) + This[i]] = "new"; }  }  returnResult;}

Main ideas:
Using the Obj object to mark the stored array element, when obj does not contain the element at this time, push the element into the result array and mark the element in the Obj object;

Places to be aware of:
    Ordinary elements can be stored directly in obj as follows: object Type + Object value , which guarantees the uniqueness of the elements and can be correctly used when the elements are "5" and 5 .
Revenue, when this element is an object, if you still store obj in this way, then you get the "Object[object object" and you can't distinguish whether the object is equal, so this
The properties and values in the object are traversed and treated as objname as the property names in obj, so that obj[objname] is used to differentiate whether each object is equal.

To test an array:
var test = [{2: "A", A: "AA"}, {2: "A", A: "AA"}, {ab: "A", A: "AA"}, {}, {}, 1,1,2, ' 2 ', ' 2 ', 3,4,5,{},{2: "A", A: "AA"}]
Test results:

JavaScript contains an array of objects to remove weight