JS instance last week next week code

Last Update:2017-01-13 Source: Internet

Author: User

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Initial page

function ini () {
Currdt = new Date ();

Showdate ();
}

Last week or next week

function Addweek (ope) {
var num = 0;
if (ope== "-") {
num =-7;
}
else if (ope== "+") {
num = 7;
}

Currdt = Adddate (currdt,num);

Showdate ();
}

function Showdate () {
span1.innerhtml = Currdt.tolocaledatestring (); Show Date

var dw = Currdt.getday ();
var Tddt;
Make sure Monday is the day
if (dw==0) {
TDDT = Adddate (currdt,-6);
}
else {
TDDT = Adddate (Currdt, (1-DW));
}

Show a week's date in a table
var OBJTB = document.getElementById ("tb1");
for (Var i=0;i<7;i++) {

if (tddt.tolocaledatestring () ==currdt.tolocaledatestring ()) {
Objtb.rows[0].cells[i].style.color = "Red"; Currdt highlighting
}

DW = Tddt.getday ();
objtb.rows[0].cells[i].innerhtml = Tddt.getmonth () +1 + "Month" + tddt.getdate () + "Day Week" + ARYDAY[DW];
TDDT = Adddate (tddt,1); Next day
}
}

Increase or decrease for several days, by positive and negative decisions of NUM, positive for Plus, minus for minus
function Adddate (dt,num) {
var ope = "+";
if (num<0) {
Ope = "-";
}

var Redt = DT;
For (var i=0;i<math.abs (num); i++) {
Redt = Addoneday (Redt,ope);
}

return Redt;
}

Increase or decrease day by ope, + for Plus,-for minus, or not moving
function Addoneday (dt,ope) {
var num = 0;
if (ope== "-") {
num =-1;
}
else if (ope== "+") {
num = 1;
}

var y = dt.getyear ();
var m = Dt.getmonth ();
var lastday = Getlastday (y,m);

var d = dt.getdate ();
d = num;
if (d<1) {
m--;
if (m<0) {
y--;
m = 11;
}
D = Getlastday (y,m);
}
else if (d>lastday) {
m++;
if (m>11) {
y++;
m = 0;
}
D = 1;
}

var Redt = new Date ();
Redt.setyear (y);
Redt.setmonth (m);
Redt.setdate (d);

return Redt;
}

Whether it is a leap year
function Isleapyear (y) {
var isleap = false;
if (y%4==0 && y%100!=0 | | y%400==0) {
Isleap = true;
}
return isleap;
}

Last day of the month
function Getlastday (y,m) {
var lastday = 28;
m++;
if (m==1 | | m==3 | | m==5 | | m==7 | | m==8 | | m==10 | | m==12) {
Lastday = 31;
}
else if (m==4 | | m==6 | | m==9 | | m==11) {
Lastday = 30;
}
else if (isleapyear (y) ==true) {
Lastday = 29;
}
return lastday;
}
</script>

This article is an English version of an article which is originally in the Chinese language on aliyun.com and is provided for information purposes only. This website makes no representation or warranty of any kind, either expressed or implied, as to the accuracy, completeness ownership or reliability of the article or any translations thereof. If you have any concerns or complaints relating to the article, please send an email, providing a detailed description of the concern or complaint, to info-contact@alibabacloud.com. A staff member will contact you within 5 working days. Once verified, infringing content will be removed immediately.

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JS instance last week next week code

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