Leetcode 152: Compare Version Numbers

Leetcode 152: Compare Version Numbers
Compare Version NumbersTotal Accepted:2468Total Submissions:17382

Compare two version numbersVersion1AndVersion1.
IfVersion1>Version2Return 1, ifVersion1<Version2Return-1, otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and.Character.
The.Character does not represent a decimal point and is used to separate number sequences.
For instance,2.5Is not "two and a half" or "half way to version three", it is the second-level revision of the second first-level revision.

Here is an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

Credits:
Special thanks to @ ts for adding this problem and creating all test cases.

public class Solution {    public int compareVersion(String version1, String version2) {        if(version1 == null || version2 ==null) return 0;                String[] v1 = version1.split("\\.");        String[] v2 = version2.split("\\.");                int n1 = v1.length;        int n2 = v2.length;                int i=0;                while(i
 
   x2) return 1;            else if(x1 < x2) return -1;            else ++i;        }                return 0;             }}