Given a non-empty integer array of size n, find the minimum number of moves required to make all array elements E Qual, where a move is incrementing n -1 elements by 1.
Example:
Input:[1,2,3]output:3explanation:only three moves is needed (remember each move increments both elements): [+]  =& gt;  [2,3,3]  =  [3,4,3]  =  [4,4,4]
Solution:
Incrementing n-1 elements by one, means every time need to increment 1 to every number except the maximum. But it's hard to implement.
Increment to every nums except Max, are as same as decrement 1 on one number until every number equals min number.
1  Public classSolution {2      Public intMinmoves (int[] nums) { 3         if(Nums. length==0)4         {5             return 0;6         }7         intn =Nums. Length;8         //Find min value in Nums;9         intMin =nums[0];Ten         foreach(intNuminchnums) One         { AMin =math.min (Min, num); -         } -          the         //Calculate the difference of every num from nums and min; ths sum should being the min Moves -         //Add 1 to n-1 are same as minus 1 from the max each time. -         intMoves =0; -         foreach(intNuminchnums) +         { -Moves + = (num-min); +         } A         returnmoves; at     } -}
Leetcode 453. Minimum Moves to Equal Array Elements C #