Leetcode Compare Version Numbers

Compare numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return-1, otherwise ret Urn 0.

Assume that the version strings is non-empty and contain only digits and the . character.
The . character does not represent a, decimal point and was used to separate number sequences.
For instance, was not "both and 2.5 a half" or "half-to-version three", it is the fifth Second-level revision of the S Econd first-level revision.

Here are an example of version numbers ordering:

0.1 < 1.1 < 1.2 < 13.37

Problem Solving Ideas:

General idea, split string with split (), Important:some special characters need to being escaped while providing them a deli Miters like "." and "\".

Then use Integer.parseint (x) to convert to an int comparison size. Note: 1.0 and 1 are equal, so when you have one string left, the value is either equal to 0 or greater than the other string.

The problem is not difficult, but easy to be wrong, careful carefully.

Java Code:

 Public intcompareversion (String version1, String version2) {string delimiter= "\\."; string[] V1=Version1.split (delimiter); String[] V2=Version2.split (delimiter); intLen =Math.max (V1.length, v2.length);  for(inti = 0; i< Len; i++){            if(I < v1.length && I <v2.length) {                if(Integer.parseint (V1[i]) >Integer.parseint (V2[i])) {                    return1; }Else if(Integer.parseint (V1[i]) <Integer.parseint (V2[i])) {                    return-1; }            }Else if(I <v1.length) {if(Integer.parseint (v1[i]) > 0) {                    return1; }            }Else if(I <v2.length) {                if(Integer.parseint (v2[i]) > 0) {                    return-1; }            }        }        return0; }

Reference:

1. http://www.programcreek.com/2014/03/leetcode-compare-version-numbers-java/

Leetcode Compare Version Numbers