"Leetcode from zero single row" No67.addbinary

Topics

Given binary strings, return their sum (also a binary string).

For example,
A ="11"
b ="1"
Return"100".

Code

public class Solution {public String addbinary (string A, string b) {string lon= a.length ()-b.length () ; =0?     A:B; String sho= a.length ()-b.length () <0?     A:B;     Char[] Lon_char=lon.tochararray ();     Char[] Sho_char=sho.tochararray ();     Char temp= ' 0 ';     int Final_length=lon.length ()-1;     int index=0;     String[] str=new string[lon.length () +1];     String addbinary_str= "";          for (int i=0;i<sho.length (); i++) {String temp_s=string.valueof (temp);          String sho_char_s=string.valueof (Sho_char[sho.length () -1-i]);          String lon_char_s=string.valueof (Lon_char[lon.length () -1-i]);              Switch (Integer.parseint (temp_s) +integer.parseint (sho_char_s) +integer.parseint (lon_char_s)) {case 0:              temp= ' 0 ';              str[index++]= "0";            Break              Case 1:temp= ' 0 ';              str[index++]= "1";            Break                Case 2:temp= ' 1 ';   str[index++]= "0";             Break                Case 3:temp= ' 1 ';                str[index++]= "1";          Break          }} while (Index<lon.length ()) {String temp_s=string.valueof (temp);                    String lon_char_s=string.valueof (Lon_char[lon.length ()-index-1]);              Switch (Integer.parseint (temp_s) +integer.parseint (lon_char_s)) {case 0:temp= ' 0 ';              str[index++]= "0";            Break              Case 1:temp= ' 0 ';              str[index++]= "1";            Break                Case 2:temp= ' 1 ';                str[index++]= "0";          Break         }} if (temp== ' 1 ') {str[lon.length ()]= "1";     Final_length=lon.length ();     } for (int k=final_length;k>=0;k--) {addbinary_str+=str[k];    } return ADDBINARY_STR; }    }

code Download: Https://github.com/jimenbian/GarvinLeetCode

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"Leetcode from zero single row" No67.addbinary