Problem description:
Given a binary tree, check whether it is a mirror of itself (ie, shortric around its center ).
For example, this binary tree is unsupported Ric:
1 / 2 2 / \ / 3 4 4 3
But the following is not:
1 / 2 2 \ 3 3
Note:
Bonus points if you cocould solve it both recursively and iteratively.
Confused what"{1, #, 2, 3 }"Means?> Read more on how binary tree is serialized on OJ.
Code:
Recursive Method
public class Symmetric_Tree { //javapublic class TreeNode { int val; TreeNode left; TreeNode right; TreeNode(int x) { val = x; } }//recursivelypublic boolean isSymmetric(TreeNode root) { if(root == null) return true; return isSymmetricTree(root.left, root.right); }public boolean isSymmetricTree(TreeNode left, TreeNode right){if(left == null && right == null)return true;if(left == null || right == null ||left.val != right.val)return false;boolean lr = isSymmetricTree(left.left, right.right);boolean rl = isSymmetricTree(left.right, right.left);return lr && rl;}}
[Leetcode] invalid Ric tree