Leetcode Oj:add Binary (binary addition)

Given binary strings, return their sum (also a binary string).

For example,
A ="11"
b ="1"
Return "100" .

Simple binary addition, except that the parameter passed in is a string. For convenience, string reverse first, the code is as follows:

1 classSolution {2  Public:3     stringAddbinary (stringAstringb) {4 Reverse (A.begin (), A.end ());5 Reverse (B.begin (), B.end ());6         intLen1 =a.length ();7         intLen2 =b.length ();8         stringresult;9         intFlag, Val;TenFlag = val =0; One         inti; A          for(i =0; I < len1 && I < len2; ++i) { -val = (A[i]-'0') + (B[i]-'0') +Flag; -Result.append (1, Val%2+'0'); theFlag = val/2; -         } -          while(I <len1) { -val = a[i]-'0'+Flag; +Result.append (1, Val%2+'0'); -Flag = val/2; +++i; A         } at          while(I <len2) { -val = b[i]-'0'+Flag; -Result.append (1, Val%2+'0'); -Flag = val/2; -++i; -         } incout <<"Flag"<< Flag <<Endl; -         if(Flag! =0) toResult.append (1,'1'); + Reverse (Result.begin (), Result.end ()); -         returnresult; the     } *};

Leetcode Oj:add Binary (binary addition)