Leetcode "Remove element"

Source: Internet
Author: User

Since no order requirement, we can simply swap the target value to the last non-target-value in the array-if the last non-target-value is not behind the current index, we are done. I got 1a:

class Solution {public:    bool move_back(int A[], int tgt, int n)    {        for (int i = n - 1; i >= 0; i--)        {            if (A[i] != A[tgt])            {                if (i <= tgt)                {                    return false; // we are done                }                else                {                    int tmp = A[i];                    A[i] = A[tgt];                    A[tgt] = tmp;                    return true;                }            }                    }        return false;    }    int removeElement(int A[], int n, int elem) {        int nCnt = n;        for (int i = 0; i < n; i++)        {            if (A[i] == elem)            {                bool bSwap = move_back(A, i, n);                if (!bSwap)                {                    nCnt = i;                    break;                }            }        }        return nCnt;    }};
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