[leetcode]107 Binary Tree level Order traversal II

Source: Internet
Author: User

https://oj.leetcode.com/problems/binary-tree-level-order-traversal-ii/

http://blog.csdn.net/linhuanmars/article/details/23414711

/** * definition for binary tree * public class treenode {  *     int val; *     TreeNode left;  *     treenode right; *     treenode (int &NBSP;X)  { val = x; } * } */public class solution {     public list<list<integer>> levelorderbottom (TreeNode root)  {        // BFS         if  (root == null)              Return collections.<list<integer>> emptylist ();                     list<list<integer >> toReturn = New arraylist<> ();        queue<treenodewithlevel>  queue = new LinkedList<TreeNodeWithLevel> ();         queue.offer (New treenodewithlevel (root, 1));         while  (!queue.isempty ())         {             treenodewithlevel n = queue.poll ();             if  (Toreturn.size ()  < n.level)             {                 toreturn.add (0, new arraylist<integer > ());            }         &nbsP;   toreturn.get (Toreturn.size ()  - n.level). Add (N.node.val);             if  (n.node.left != null)              {                 queue.offer (New treenodewithlevel (n.node.left, n.level  + 1));            }             if  (n.node.right != null)              {                 queue.offer (New treenodewithlevel (n.node.right,  n.level + 1));            }        &nBSP;}         return toReturn;    }         private static class TreeNodeWithLevel     {        int level;         treenode node;        treenodewithlevel (TreeNode  node, int level)         {             this.node = node;             this.level = level;         }    }}


[leetcode]107 Binary Tree level Order traversal II

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