Section 3 arithmetic operations of phalanx
I. phalanx power
The k-th power of matrix A is counted as Ak.
Rules
Matrix Multiplication is suitable for combination laws, so the calculation of phalanx meets the following calculation rules:
Example 9
Solution:
Ii. Determining the phalanx
Definition 6NSquare MatrixAIs called a square matrix.AIs counted as |A| Or detA.
Example 10
Solution:
Note: The Order n square matrix is a number table, and the Order n determines a number.
The determining factor of the square matrix satisfies the following rules:
(1) |At| = |A|;
(2) |La| =LN|A|;
(3) |AB| = |A|B|, Similarly, |Ba| = |B|A|
From (3) We can see that for the n-order Determinant A and B, AB is generally equal to BA, but | BA | = | AB |.
Example 11
Solution:
It can also be interpreted
Define 7 square arrays of order nA|A| Algebra of each elementAIJThe transpose matrix of the n-order matrixA.
Note: | A | the algebraic remainder of each element in row I is located in column I (I = 1, 2 ,..., N ).
Solution:
We can see from the theorem in the Determinant
So
Likewise verifiable
The conclusion is as follows:
Solution:
Iii. Inverse of phalanx
Definition 8NLevel MatrixA, If yesNLevel MatrixB, MakingAB=Ba=En,
Then MatrixAIs a reversible or non-singular matrix, andBIsA.
AThe inverse array B of is counted as B =A-1.
Reversible matrices are mutual, B is the inverse matrix of A, and A is also the inverse matrix of B, and A and B are mutually inverse matrices.
That is, ifAB=Ba=E
, ThenB=A-1,A=B-1.
For example, for a second-order square matrix and a second-order square matrix
A and B are reversible matrices, and they are inverse matrices.
The inverse matrix has the following properties:
(1) uniqueness: If the MatrixAIs reversible, soAIs unique.
Proof: Because ifBN andCnAllAThe inverse matrix
AB=BA=E,
AC=CA=E,
ThereforeB=BE=B(AC) = (AB)C=EC=C
That isB=C
Therefore, the inverse matrix is unique.
(2) IfAReversible, thenA-1 is also reversible, and (A-1)-1 =A;
(3) IfAReversible, numberKLimit 0, thenKAReversible, and;
Proof:
(4) IfAReversible, thenATAnd (AT)-1 = (A-1)T
.
Proof: Because
AT(A-1)T= (A-1A)T=ET=E.
(A-1)T
= (A-1)T=ET=E.
So (AT)-1 = (A-1)T
.
(5) IfA,BFor the same-order reversible matrixABAnd (AB)-1 =B-1A-1.
This is because
(AB)(B-1A-1) =A(BB-1)A-1 =AEA-1 =AA-1 =E.
(B-1A-1 )(AB) =B-1 (A-1A)B
=B-1EB=B-1B=E.
So (AB)-1 =B-1A-1.
This property can also be extended to A finite matrix, such as A, B ,..., C is a reversible matrix.
(AB... C)-1 = C-1... B-1A-1.
Theorem 1 it is necessary and sufficient for n-order square matrix A to be reversible. The condition is | A | ≠ 0, and
CertificateNecessity:
A n-order matrix A-1 is known to be reversible, making
AA-1 = A-1A = En,
Because | AA-1 | = | A-1 | A | = | En | = 1,
So |A| Limit 0,
The property AA * = A * A = | A | E,
D,
Likewise
Therefore, according to the definition of the inverse arrayAReversible and
.
Adequacy (omitted)
In combination, the matrixAReversible license |A| Limit 0; ifAReversible, then
Theorem 1 not only provides the impulsive conditions for the existence of the inverse matrix, but also provides A method for finding the inverse matrix, that is, first finding the determinant of the known square matrix | A |, if |A| Limit 0. We can see that A is reversible and further calculated.
Solution:
The reversible nature of matrices can solve many complex problems.
For example, set a Linear EquationsAx = B,If A is A n-order reversible matrix, then the two sides of the equation are left by the A-1
A-1Ax =A-1B
ThenX =A-1BLinear EquationsAx = B.
Solution: known Coefficient Matrix
Therefore, a is a third-order reversible matrix.