Nine degree OJ 1062 segment function (analog)

Topic 1062: Segmented functions

time limit:1 seconds

Memory limit:32 MB

Special question: No

submitted:2877

Resolution:1671

Title Description:

Write a program that calculates the value of the following segment function, Y=f (x).
y=-x+2.5; 0<=x<2
y=2-1.5 (x-3) (x-3); 2<=x<4
y=x/2-1.5; 4<=x<6

Input:

A floating-point number n

Output:

The test data may have multiple groups, for each set of data,
Output N corresponds to the piecewise function value: F (n). Results retain three decimal places

Sample input:

1

Sample output:

1.500

#include <stdio.h> #include <stdlib.h> #include <string.h>double y (double x) {    double result;    if (0<=x&&x<2.0)    {        result=-1*x+2.5;    }    else if (2<=x&&x<4) {        result=2-1.5* (x-3.0) * (x-3.0);    }    else{        result=x/2-1.5;    }    return result;} int main (int argc, char *argv[]) {    freopen ("1062.in", "R", stdin);    Double N;    while (~SCANF ("%lf", &n))    {        printf ("%.3lf\n", Y (N));    }    return 0;}

Nine degree OJ 1062 segment function (analog)