Nine degrees oj-topic 1032:zoj

Title Description:

read into a string, the string contains zoj three characters, the number is not necessarily equal, in the order of zoj output, when a character runs out, the rest is still in the order of zoj output.

Input:

The topic contains multiple sets of use cases, one for each group of use cases, containing zoj three characters, and the end of the input when the "E" is entered.
1<=length<=100.

Output:

For each set of inputs, output a line that represents the string after processing as required.
A concrete example of the visible sample.

Sample input:

Zzooojjjzzzzooooojjjzooojje

Sample output:

Zojzojojzojzojzojzoozojojo

Source:

2009 Zhejiang University computer and software engineering research on the real problem of life test

Answering:

problem solving problems? to discuss the subject of discussion please visit: http://t.jobdu.com/thread-7756-1-1.html

    #include <stdio.h> #include <string.h> int main () {char s[100];        int i;            while (scanf ("%s", s)!=eof) {if (strcmp (S, "E") ==0) break;            int z=0,o=0,j=0;                for (i=0;s[i]!= '; i++) {if (s[i]== ' Z ') z++;                else if (s[i]== ' O ') o++;               else J + +;                    } if (Z>o) {if (o>j) {//Z o J for (i=0;i<j;i++) printf ("ZOJ");                    for (i=0;i<o-j;i++) printf ("ZO");                for (i=0;i<z-o;i++) printf ("Z");                    } else if (z>j) {//Z J O for (i=0;i<o;i++) printf ("ZOJ");                    for (i=0;i<j-o;i++) printf ("ZJ");                           for (i=0;i<z-j;i++) printf ("Z");                    } else{//J Z o for (i=0;i<o;i++) printf ("ZOJ");                    for (i=0;i<z-o;i++) printf ("ZJ"); for (i=0;i<j-z;i++) printf ("J");                    }}else {if (z>j) {//O Z J for (i=0;i<j;i++) printf ("ZOJ");                    for (i=0;i<z-j;i++) printf ("ZO");                for (i=0;i<o-z;i++) printf ("O");                    } else if (J>o) {//J O Z for (i=0;i<z;i++) printf ("ZOJ");                    for (i=0;i<o-z;i++) printf ("OJ");                for (i=0;i<j-o;i++) printf ("J");                    } else {//O J Z for (i=0;i<z;i++) printf ("ZOJ");                    for (i=0;i<j-z;i++) printf ("OJ");                for (i=0;i<o-j;i++) printf ("O");        }} printf ("\ n");       } return 0; }/************************************************************** problem:1032 User:vhreal Langu Age:c result:accepted time:0 Ms memory:912 KB ****************************************************************/ 

Nine degrees oj-topic 1032:zoj