Php error: unexpected '$ staff'

This is the source code: {code...} and then the error: Parseerror: syntaxerror, unexpected & #039; $ staff & #039; (T_VARIABLE) inD: wampwwwtestquery. phponline4 this is the source code:

   "x","number" => "101","sex" => "male","job" => "manager"),        array("name" => "y","number" => "102","sex" => "male","job" => "manager"),        array("name" => "z","number" => "103","sex" => "male","job" => "manager"),    );if ($_SERVER["REQUEST_METHOD"] == "GET") {    search();}elseif ($_SERVER["REQUEST_METHOD"] == "POST") {    create();}function search() {    if (!isset($_GET["number"]) || empty($_GET["number"])) {        echo "error";        return;    }    global $staff    $number = $_GET["number"];    $result = "error";    foreach ($staff as $key => $value) {        if ($value["number"] == $number) {            $result = "The person's ID is".$value["number;"]."He's name is".$value["name;"]."And sex is".$value["sex"]."The job".$value["job"];            break;        }    }    echo $result;}function create() {    if (!isset($_POST["name"]) || empty($_POST["name"]) ||        !isset($_POST["number"]) || empty($_POST["number"]) ||        !isset($_POST["sex"]) || empty($_POST["sex"]) ||        !isset($_POST["job"]) || empty($_POST["job"]) {        echo "error";        return;    }    echo "The person".$_POST["name"]."save success";} ?> 

Then an error is reported:
Parse error: syntax error, unexpected '$ staff' (T_VARIABLE) in D: \ wamp \ www \ test \ query. php on line 4

Reply content:

This is the source code:

   "x","number" => "101","sex" => "male","job" => "manager"),        array("name" => "y","number" => "102","sex" => "male","job" => "manager"),        array("name" => "z","number" => "103","sex" => "male","job" => "manager"),    );if ($_SERVER["REQUEST_METHOD"] == "GET") {    search();}elseif ($_SERVER["REQUEST_METHOD"] == "POST") {    create();}function search() {    if (!isset($_GET["number"]) || empty($_GET["number"])) {        echo "error";        return;    }    global $staff    $number = $_GET["number"];    $result = "error";    foreach ($staff as $key => $value) {        if ($value["number"] == $number) {            $result = "The person's ID is".$value["number;"]."He's name is".$value["name;"]."And sex is".$value["sex"]."The job".$value["job"];            break;        }    }    echo $result;}function create() {    if (!isset($_POST["name"]) || empty($_POST["name"]) ||        !isset($_POST["number"]) || empty($_POST["number"]) ||        !isset($_POST["sex"]) || empty($_POST["sex"]) ||        !isset($_POST["job"]) || empty($_POST["job"]) {        echo "error";        return;    }    echo "The person".$_POST["name"]."save success";} ?> 

Then an error is reported:
Parse error: syntax error, unexpected '$ staff' (T_VARIABLE) in D: \ wamp \ www \ test \ query. php on line 4

$staffHeader () does not use a semicolon;End. Syntax error.
Lines 21 and 36 also have
It is better for beginners to use an ide.

The change is as follows:

   "x","number" => "101","sex" => "male","job" => "manager"),        array("name" => "y","number" => "102","sex" => "male","job" => "manager"),        array("name" => "z","number" => "103","sex" => "male","job" => "manager"),    );

Rows 22 and 36 are also incorrect.